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Dima020 [189]
3 years ago
12

Is this a function if it is please show your work and explain why.

Mathematics
1 answer:
Gnom [1K]3 years ago
8 0

9514 1404 393

Answer:

  not a function

Step-by-step explanation:

When a left-side point originates more than 1 arrow, the relation is not a function. There are two such points here, so this relation is not a function.

You might be interested in
Otieno is k years old.He is 5 years older than kidole what will be their age fours to come​
EleoNora [17]

Answer:

Otieno's age in 4 years: k+4

Kidole's age in 4 years: k-1

Step-by-step explanation:

k = Otieno's age

k-5 = Kidole's age

Their ages will increase by 4 years when 4 years pass.

k+4 = Otieno's age in 4 years

k-5+4 = Kidole's age in 4 years

k-1 = Kidole's age in 4 years (after simplifying the expression)

I hope this helps!

6 0
3 years ago
Which of the following numbers are NOT rational?<br> A)√25<br> B)18.9238...<br> C)1.323232...
Elena-2011 [213]

Answer:

the answer is a because it has no decimal

it is in square root

4 0
3 years ago
Factor the polynomial.<br> 13x² – 20x – 12
erma4kov [3.2K]

Answer:

(13 x + 6) (x - 2)

Step-by-step explanation:

Factor the following:

13 x^2 - 20 x - 12

Factor the quadratic 13 x^2 - 20 x - 12. The coefficient of x^2 is 13 and the constant term is -12. The product of 13 and -12 is -156. The factors of -156 which sum to -20 are 6 and -26. So 13 x^2 - 20 x - 12 = 13 x^2 - 26 x + 6 x - 12 = x (13 x + 6) - 2 (13 x + 6):

x (13 x + 6) - 2 (13 x + 6)

Factor 13 x + 6 from x (13 x + 6) - 2 (13 x + 6):

Answer: (13 x + 6) (x - 2)

6 0
3 years ago
Solve for x. ax-bx=k​
dolphi86 [110]

Answer:

x= k/a-b

Step-by-step explanation:

Move all terms to the left side and set equal to zero as well as each factor.

Hope this helps.

3 0
3 years ago
Read 2 more answers
Suppose y varies directly as x and y=21 when x=7. which is an equation relating x and y
astra-53 [7]
Y varies directly as x: y=kx, k is a constant.
when x=7, y=21, so we know k=3
therefore, the equation is y=3x
8 0
3 years ago
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