All categories

3 years ago

Please help it is math related

Mathematics

1 answer:

soldi70 [24.7K]3 years ago

4 0

Answer:

The slope is 3/8!

Explanation:

You put your equation in slope-intercept form, that is how you find the slope.

3x-8y=-20

-8y=-3x-20

y=3/8x-20

the fraction is now positive because the numerator and the denominator are both negative so they are changed into positive.

Hope This Helps!

You might be interested in

What is the radical expression of a4/9

Papessa [141]

Hi there!

Please see the picture below for the answer.

Thanks!

Good luck!

7 0

3 years ago

Please help me on thissss

cupoosta [38]

Answer:No its not a function

Step-by-step explanation:

8 0

3 years ago

PLEASE HELP ASAP

Shtirlitz [24]

Answer:

i think its photosinthisis because...

Step-by-step explanation:

Sometime around 3 billion years ago (about 1.5 billion years after Earth formed!), photosynthesis began. Photosynthesis allowed organisms to use sunlight and inorganic molecules, such as carbon dioxide and water, to create chemical energy that they could use for food.

Hope this helps and maybe a brainlest?

8 0

3 years ago

The vertices of a triangle are labeled clockwise A(–5, 3), B(6, 1), and C(–2, –3). How could you show that the figure is a right

mafiozo [28]

Explanation:

When the points are plotted on a graph, it is easy to see that the slope of AC is -2 and the slope of BC is 1/2. These slope values have a product of -1, so the corresponding line segments are perpendicular to each other.

___

If you have studied vectors, you can find the dot product of AC with BC:

AC = (-5, 3) -(-2, -3) = (-3, 6)

BC = (6, 1) -(-2, -3) = (8, 4)

The dot product is ...

(-3, 6)·(8, 4) = (-3)(8) + (6)(4) = -24+24 = 0

When the dot product of vectors is zero, they are perpendicular.

5 0

3 years ago

The answer is red show step by step of the pro tem to get the answer

miskamm [114]

In order to rationalize the denominator of each expression, we need to multiply the expression by the same radical in the denominator, this way we can remove the radical from the denominator.

$\frac{5\sqrt{4}}{\sqrt{3}}(\cdot\sqrt{3})=\frac{5\sqrt{4}\sqrt{3}}{(\sqrt{3})^2}=\frac{5\cdot2\cdot\sqrt{3}}{3}=\frac{10\sqrt{3}}{3}$

10)

$-\frac{5}{3\sqrt{2}}(\cdot\sqrt{2})=-\frac{5\sqrt{2}}{3(\sqrt{2})^2}=-\frac{5\sqrt{2}}{3\cdot2}=-\frac{5\sqrt{2}}{6}$

11)

$\frac{2\sqrt{3}}{4\sqrt{5}}(\cdot\sqrt{5})=\frac{2\sqrt{3}\sqrt{5}}{4(\sqrt{5})^2}=\frac{2\sqrt{15}}{4\cdot5}=\frac{\sqrt{15}}{2\cdot5}=\frac{\sqrt{15}}{10}$

12)

$\frac{\sqrt{5}}{\sqrt{2}}(\cdot\sqrt{2})=\frac{\sqrt{5}\sqrt{2}}{(\sqrt{2})^2}=\frac{\sqrt{10}}{2}$

3 0

1 year ago