Answer:
C. (4,-7)
Step-by-step explanation:
To answer this question, I just graphed the two equations. Then I found where they intersected.
The standard form for the equation of a circle is :
<span><span><span> (x−h)^</span>2</span>+<span><span>(y−k)^</span>2</span>=<span>r2</span></span><span> ----------- EQ(1)
</span><span> where </span><span>handk</span><span> are the </span><span>x and y</span><span> coordinates of the center of the circle and </span>r<span> is the radius.
</span> The center of the circle is the midpoint of the diameter.
So the midpoint of the diameter with endpoints at (−10,1)and(−8,5) is :
((−10+(−8))/2,(1+5)/2)=(−9,3)
So the point (−9,3) is the center of the circle.
Now, use the distance formula to find the radius of the circle:
r^2=(−10−(−9))^2+(1−3)^2=1+4=5
⇒r=√5
Subtituting h=−9, k=3 and r=√5 into EQ(1) gives :
(x+9)^2+(y−3)^2=5
Answer:
x and y do not show direct variation.
Step-by-step explanation:
The formula for direct variation is
y = kx Divide each side by y
k = y/x
k should have the same value for every point except, of course, (0,0)
For the first point,
k = 2/(-1) = -2
For the third point,
k = 2/1 = 2
The values of k are different, so x and y <em>do not</em> show direct variation.
Answer:
TRUE
Step-by-step explanation:
Answer:
$7,367.43
Step-by-step explanation:
