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bagirrra123 [75]
3 years ago
6

C-28 how do you solve this problem ​

Mathematics
1 answer:
Jobisdone [24]3 years ago
4 0

Answer:

  The FitnessGram™ Pacer Test is a multistage aerobic capacity test that progressively gets more difficult as it continues. The 20 meter pacer test will begin in 30 seconds. Line up at the start. The running speed starts slowly, but gets faster each minute after you hear this signal. Ding  A single lap should be completed each time you hear this sound. Ding  Remember to run in a straight line, and run as long as possible. The second time you fail to complete a lap before the sound, your test is over. The test will begin on the word start. On your mark, get ready, ding

Any=ways berainalieast?

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Find the equation of the line that has slope 2/3 and which passes through (-1,-4)
Masja [62]
The answer is y=2/3x+5
8 0
4 years ago
Find the surface area of a square pyramid with side length 1 and slant height 2.
Lelu [443]

Answer:

Simply search for surface area formula for pyramid on goole and plug the numbers into the formula!! Thank you so much!!

Step-by-step explanation:

6 0
3 years ago
Greg started baking at 6:05 PM and finished at 7:42 PM.
FrozenT [24]

Answer:

97 minutes

Step-by-step explanation:

Starting at 6:05, it will take 55 minutes to get to 7:00. Then you can add the 42 minutes to the 55 to get a total amount. This results in 97 minutes in total for your answer.

8 0
3 years ago
Read 2 more answers
.<br> What is (4x2-9X+1) -(5x2-x-7) written in standard form?
bija089 [108]

Answer:

(9-9x) - (3-x)

Step-by-step explanation:

(4x2 -9x +1) - (5x2 -x -7)

4x2+1= 9. 5x2-7= 3

(9-9x) - ( 3-x)

7 0
3 years ago
Part 4: Use the information provided to write the standard form equation of each equation
dedylja [7]

Problem 10

<h3>Answer:   (x+5)^2+(y-3)^2=25</h3>

------------

Work Shown:

All we're doing really is replacing the original 'y' with 'y-3' to shift the center up 3 units. This shifts every point on the circle the same as well.

This new circle has center (-5,3) and radius 5. The old center was (-5,0). The radius stayed the same.

===========================================================

Problem 11

<h3>Answer:  (x-8)^2+(y-15)^2 = 9</h3>

------------

Work Shown:

x^2+y^2-16x-30y+280 = 0

(x^2-16x)+(y^2-30y)+280 = 0

(x^2-16x+64)-64+(y^2-30y+225)-225+280 = 0

(x-8)^2+(y-15)^2-9 = 0

(x-8)^2+(y-15)^2 = 9

This circle has center (8,15) and radius 3.

===========================================================

Problem 12

<h3>Answer:  (x+6)^2+(y-11)^2 = 20</h3>

------------

Work Shown:

x^2+y^2+12x-22y+137 = 0

(x^2+12x)+(y^2-22y)+137 = 0

(x^2+12x+36)-36+(y^2-22y+121)-121+137 = 0

(x+6)^2+(y-11)^2-20 = 0

(x+6)^2+(y-11)^2 = 20

This circle has center (-6,11) and radius sqrt(20) = 2*sqrt(5).

5 0
3 years ago
Read 2 more answers
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