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tresset_1 [31]
3 years ago
13

A class of 63 students is going on a field trip. They will take 9 buses. Each bus will have the same number of students. How man

y students will be on each bus? ​
Mathematics
2 answers:
SSSSS [86.1K]3 years ago
3 0

Answer:

There will be 7 students on each bus.

Step-by-step explanation:

If the class of 63 students is divided into 9 buses with the same number of students traveling in each one, to determine the number of students traveling in each bus it is necessary to perform the following mathematical calculation:

63/9 = X

7 = X

Thus, in each bus 7 students will travel, and in this way all buses will carry the same number of students.

Citrus2011 [14]3 years ago
3 0

Answer:

9

Step-by-step explanation:

36 divided by 4 = 9

:)))

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zhannawk [14.2K]

Step-by-step explanation:

4/5 + 2/3 = 2215 = 1 715 ≅ 1.4666667. Spelled result in words is twenty-two fifteenths (or one and seven fifteenths).

5 0
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Answer:

x1=((2√3)/3)i

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Step-by-step explanation:

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Find the solution set of this inequality|10x+20| ≤10
Pavlova-9 [17]

Answer:

solution is

[-3,-1]

Step-by-step explanation:

we are given

|10x+20|\leq 10

Firstly, we will find critical values

so, let's assume it is equal

|10x+20|= 10

now, we can break absolute sign

For |10x+20|= -(10x+20):

-(10x+20)= 10

we can solve for x

-10x-20= 10

Add both sides by 20

-10x-20+20= 10+20

-10x= 30

Divide both sides by -10

and we get

x=-3

For |10x+20|= (10x+20):

(10x+20)= 10

we can solve for x

10x+20= 10

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10x+20-20= 10-20

10x= -10

Divide both sides by 10

and we get

x=-1

so, critical values are

x=-3

x=-1

now, we can draw a number line and locate these values

and then we can check inequality on each intervals

For (-\infty,-3):

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-5

|10\times -5+20|\leq 10

|-50+20|\leq 10

30\leq 10

so, this is FALSE

For [-3,-1]:

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-2

|10\times -2+20|\leq 10

|-20+20|\leq 10

0\leq 10

so, this is TRUE

For (-1,\infty):

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=0

|10\times 0+20|\leq 10

|0+20|\leq 10

20\leq 10

so, this is FALSE

so, solution is

[-3,-1]

7 0
3 years ago
7 less than three fifths of b is a
Citrus2011 [14]
It would be 3/5b-7=y?
4 0
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Find the HCF of 20,55,90<br> Pls help it is urgent if i dont get this answer i will fail
Ann [662]

Answer:

Step-by-step explanation:

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