David performed the following mathematical operation:
1 answer:
Answer:
B. 1 must be a root of the polynomial 3x^2+x-4
Step-by-step explanation:
Given polynomial
3x^2+x-4
Divided by factor x-1
Gives a remainder of 0
Remainder 0 represents that divisor (x-1) is a factor polynomial 3x^2+x-4
If x-1 is a factor of the polynomial, we can equate x-1 to 0
x-1=0
Solve for x to get one of the roots
x-1=0
Add 1 to both sides
x-1+1=0+1
x=1
B. 1 must be a root of the polynomial 3x^2+x-4
You might be interested in
Answer:
B
Step-by-step explanation:
+ 6 = x ( subtract 6 from both sides )
= x - 6 ( square both sides )
x = (x - 6)² ← expand using FOIL
x = x² - 12x + 36 ( subtract x from both sides )
0 = x² - 13x + 36 , that is
x² - 13x + 36 = 0 ← in standard form
(x - 4)(x - 9) = 0 ← in factored form
Equate each factor to zero and solve for x
x - 4 = 0 ⇒ x = 4
x - 9 = 0 ⇒ x = 9
As a check
Substitute these values into the equation and if both sides are equal then they are the solutions.
x = 4
left side = + 6 = 2 + 6 = 8
right side = x = 4
Since 8 ≠ 4 then x = 4 is an extraneous solution
x = 9
left side = + 6 = 3 + 6 = 9
right side = x = 9
Thus the solution is x = 9 → B