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3 years ago

Reduce 6/33 to lowest terms

Mathematics

2 answers:

balandron [24]3 years ago

8 0

$\frac{6}{33}^{(3}\to\boxed{\frac{2}{11}}$

Vitek1552 [10]3 years ago

3 0

The lowest term pf 6/33 is 2 over 11

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A car valued at £18000 at the start of 2017, depreciated in value by 5% each year for 3 years. How much did it lose in value ove

Anna11 [10]

Answer:

The amount lost over the 3 years s 2567.25£

Explanation:

$\mathrm{F}=\mathrm{I} \times\left(1-\left(\frac{r}{100}\right)\right)^{\mathrm{n}}$

where F = final value after n years

I = initial value of the car in 2017 = £18000 (given)

Since the value is depreciated 5% every year for 3 years,

r = percentage rate of depreciation = 5% (given)

n = 3 years

Substituting these values in formula, we get

$\mathrm{F}=18000 \times\left(1-\frac{5}{100}\right)^{3}$

= $18000 \times\left(\frac{95}{100}\right)^{3}$

= 15432.75£ which is the value of the car after 3 years

Finally 18000-15432.75 = 2567.25£ is the amount lost over this period.

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3 years ago

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vodomira [7]

Answer:

y=15

Step-by-step explanation:

y-7=8

Add 7 to each side to cancel out the 7 next to the variable.

You get y=15.

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Remove parentheses and simplify 7a+6b-4 (3a-3b)

Varvara68 [4.7K]

Normally, you would do whatever is inside of the parenthesees first then do the rest but we cant get any further so we remove the parenthasees by distrubtion

7a+6b-4(3a-3b)
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a(b+c)=(ab)+(ac)
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7a+6b-12a+12b
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that's the asnwer

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real numbers hope it helps

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daser333 [38]

The x intercept would be on (-2,0)

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