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rjkz [21]
3 years ago
14

Reduce 6/33 to lowest terms

Mathematics
2 answers:
balandron [24]3 years ago
8 0
\frac{6}{33}^{(3}\to\boxed{\frac{2}{11}}
Vitek1552 [10]3 years ago
3 0
The lowest term pf 6/33 is 2 over 11
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A car valued at £18000 at the start of 2017, depreciated in value by 5% each year for 3 years. How much did it lose in value ove
Anna11 [10]

<u>Answer:</u>

The amount lost over the 3 years s 2567.25£  

<u>Explanation:</u>

$\mathrm{F}=\mathrm{I} \times\left(1-\left(\frac{r}{100}\right)\right)^{\mathrm{n}}$

where F = final value after n years

I = initial value of the car in 2017 = £18000 (given)

Since the value is depreciated 5% every year for 3 years,

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Substituting these values in formula, we get

$\mathrm{F}=18000 \times\left(1-\frac{5}{100}\right)^{3}$

= $18000 \times\left(\frac{95}{100}\right)^{3}$

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Finally 18000-15432.75 = 2567.25£ is the amount lost over this period.  

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