All categories

3 years ago

Will paid $2.73 for 3.5 pounds of bananas. What was the cost per pound of the bananas?

Mathematics

1 answer:

Alex73 [517]3 years ago

5 0

Answer:

0.78¢

Step-by-step explanation:

if 3.5 lbs of bananas is $2.73, then we need to divide each side by 3.5 to get 1 lb of bananas

1 lb = 0.78¢

To check our work, we can do 0.78x3.5 = 2.73

Hope this helps! Please mark Brainliest if this helped :)

You might be interested in

A clothing sells 26 shirts and 22 pairs of jeans. Each item of clothing costs $32. What is a reasonable estimate for the total c

jasenka [17]

Answer:

Exact-$1,536 Estimate-$1,500

Step-by-step explanation:

26+22=48

48 x 32 = 1,536

Estimate-1,500 or 1,540

Exact-1,536

6 0

3 years ago

Read 2 more answers

If pie is round then does that mean its also pi(3.14)

Papessa [141]

Answer:

no because if your talking about like pumpkin pie or apple pie the the pie or pie tin has a circumference when pi 3.14 is an ongoing number.

5 0

2 years ago

Read 2 more answers

Write the equation -4x^2+9y^2+32x+36y-64=0 in standard form. Please show me each step of the process!

IgorC [24]

Hey there, hope I can help!

$-4x^2+9y^2+32x+36y-64=0$

$\mathrm{Add\:}64\mathrm{\:to\:both\:sides} \ \textgreater \ 9y^2+32x+36y-4x^2=64$

$\mathrm{Factor\:out\:coefficient\:of\:square\:terms} \ \textgreater \ -4\left(x^2-8x\right)+9\left(y^2+4y\right)=64$

$\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}4$
$-\left(x^2-8x\right)+\frac{9}{4}\left(y^2+4y\right)=16$

$\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}9$
$-\frac{1}{9}\left(x^2-8x\right)+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}$

$\mathrm{Convert}\:x\:\mathrm{to\:square\:form}$
$-\frac{1}{9}\left(x^2-8x+16\right)+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)$

$\mathrm{Convert\:to\:square\:form}$
$-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)$

$\mathrm{Convert}\:y\:\mathrm{to\:square\:form}$
$-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y^2+4y+4\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right)$

$\mathrm{Convert\:to\:square\:form}$
$-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y+2\right)^2=\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right)$

$\mathrm{Refine\:}\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right) \ \textgreater \ -\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y+2\right)^2=1$

$Refine\;once\;more\;-\frac{\left(x-4\right)^2}{9}+\frac{\left(y+2\right)^2}{4}=1$

For me I used
$\frac{\left(y-k\right)^2}{a^2}-\frac{\left(x-h\right)^2}{b^2}= 1$
$As\;\mathrm{it\;\:is\:the\:standard\:equation\:for\:an\:up-down\:facing\:hyperbola}$

I know yours is an equation which is why I did not go any further because this is the standard form you are looking for. I would rewrite mine to get my hyperbola standard form. However the one I have provided is the form you need where mine would be.
$\frac{\left(y-\left(-2\right)\right)^2}{2^2}-\frac{\left(x-4\right)^2}{3^2}=1$

Hope this helps!

4 0

3 years ago

If x = -4, calculate 2x squared - 5

Varvara68 [4.7K]

You just substitute the value of x in the given equation:

f(x) = 2x^2 - 5

f(-4) = 2 (-4)^2 -5 = 27

f(x) : a name given to the equation
f(-4): refer to the equation when the value of the independent variable x has the value between the brackets.

5 0

3 years ago

A shop sells sweets where every 3 sweet wrappers can be exchanged for one more sweet. Kelvin has enough money to buy only 19 swe

drek231 [11]

Answer:

Kelvin can get 6 free sweets

6 0

1 year ago