Answer:
The smaller bottle holds 12.5 ml of perfume.
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<h2>Given</h2>
- Two bottles of similar shape;
- Larger bottle has volume of 100 ml;
- The length of larger bottle is 10 cm;
- The length of smaller bottle is 5 cm.
<h2>To find </h2>
- The volume of smaller bottle.
<h2>Solution</h2>
Find the scale factor, the ratio of corresponding dimensions:
We know the volume is the function of three dimensions, therefore the ratio of volumes is the cube of the scale factor:
Substitute the known values and find the volume of small bottle:
The smaller bottle holds 12.5 ml of perfume.
Step-by-step explanation:
Put a open circle at 1 1/2 then draw a line going to the left of 1 1/2
The answer is: [A]: " 20a − 5b − 9 " .
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Explanation:
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(12a <span>+ 7b) + (−6a − 9) + (14a − 12b) =
12a </span><span>+ 7b + 1(−6a − 9) + 1(14a − 12b) =
</span>
12a + 7b + (1*-6a) + (1*-9) + (1*14a) + (1* -12b) =
12a + 7b − 6a − 9 + 14a − 12b = ?
Combine the "like terms:
12a − 6a + 14a = 20a ;
7b − 12b = - 5b ;
and then we have "-9" ;
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So, write as: " 20a − 5b − 9 " ; which is: Answer choice: [A].
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Answer:
Step-by-step explanation:
d = 3/2
a₂₀ = a₁+19d
35/2 = a₁ + 19×3/2
a₁ = 35/2 - 19×3/2 = -11
a₁₅ = a₁+14d = -11 + 14×3/2 = 10
