<h3>
Answer: $4.46</h3>
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Work Shown:
3 containers = 6.69 dollars
3/3 containers = 6.69/3 dollars .... divide both sides by 3
1 container = 2.23 dollars
2*(1 container) = 2*(2.23 dollars) ... multiply both sides by 2
2 containers = 4.46 dollars
A shortcut is to start with "3 containers = 6.69 dollars" and multiply both sides by 2/3
Each mention of "container" refers to a half-gallon container.
Answer:
8 brownies
Step-by-step explanation:
Let's figure out how many brownies the class ate
Multiply 48* 5/6=40
Then, subtract how many the class ate from the total
48-40=8
So, he brought home 8 brownies
Hope this helped!
By using the concept of uniform rectilinear motion, the distance surplus of the average race car is equal to 3 / 4 miles. (Right choice: A)
<h3>How many more distance does the average race car travels than the average consumer car?</h3>
In accordance with the statement, both the average consumer car and the average race car travel at constant speed (v), in miles per hour. The distance traveled by the vehicle (s), in miles, is equal to the product of the speed and time (t), in hours. The distance surplus (s'), in miles, done by the average race car is determined by the following expression:
s' = (v' - v) · t
Where:
- v' - Speed of the average race car, in miles per hour.
- v - Speed of the average consumer car, in miles per hour.
- t - Time, in hours.
Please notice that a hour equal 3600 seconds. If we know that v' = 210 mi / h, v = 120 mi / h and t = 30 / 3600 h, then the distance surplus of the average race car is:
s' = (210 - 120) · (30 / 3600)
s' = 3 / 4 mi
The distance surplus of the average race car is equal to 3 / 4 miles.
To learn more on uniform rectilinear motion: brainly.com/question/10153269
#SPJ1
The answer would be 5*C or 5C or 5(C) they all mean the same exact thing but if Kevin has 5 times as much no matter what billy has you’ll have to multiply that by 5 to see how much Kevin’s has so if billy has c then you multiply that by 5
For example, x/2 - x/3 = 1 => (3x)/6 - (2x)/6 = 6/6 => 3x - 2x = 6 => x = 6;
