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ASHA 777 [7]
3 years ago
6

The local newspaper has letters to the editor from 80 people. If this number represents 5 ​% of all of the​ newspaper's readers,

how many readers does the newspaper​ have?
Mathematics
1 answer:
Elden [556K]3 years ago
8 0

Answer:

The newspaper has 1,600 readers.

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A car traveling at 32 m/s starts to decelerate steadily. It comes to a complete stop in 14 seconds. What is its acceleration?
valentina_108 [34]
We have:

Initial velocity (u) = 32 m/s
Final velocity (v) = 0 m/s ⇒ The value is zero because the car comes to stationary position when it stops
Time = 14 seconds

We can use one of the constant acceleration equation:
v=u+at where a is the acceleration

0=32+14a
32=-14a
a=- \frac{32}{14}=-2.3m/s^{-2}

The acceleration is 2.3 m/s⁻² and the negative sign shows deceleration
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3 years ago
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MATH HELP ASAP!! MARKING BRAINLIST
Hunter-Best [27]

Answer:

f(2)=0

Step-by-step explanation:

f(2)=2x-4

2(2)-4

4-4

0

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2 years ago
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A couch and coffee table cost a total of $1044 . The cost of the couch is three times the cost of the coffee table. Find the cos
Irina18 [472]
3x + x = 1044

4x = 1044 - divide both sides by four

x = 261

coffee table - $261
couch - $783
4 0
3 years ago
A university president proposed that all students must take a course in ethics as a requirement for graduation. Three hundred fa
mash [69]

You did not add the attachment for this question to be answered. I have added it

Answer:

0.5333

Step-by-step explanation:

We have

P(faculty) to be the probability of faculty being selected

= 70/300

= 0.233333333

We also have

P(favor) to be the probability of being in favor of this proposal

= 135/300

= 0.45

In answer to this question,

The required probability

= P(faculty) + p(favor) - p(faculty n favor)

p(faculty n favor) = 45/300

= 0.15

Probability = 0.233333333 + 0.45- 0.15

= 0.5333 approximately

8 0
2 years ago
Find the deriative dy/dx for y=x^2-2x/x^3+3
vaieri [72.5K]

Answer:

\frac{dy}{dx}=(\frac{(2x-2)(x^3+3)-(x^2-2x)(3x^2)}{(x^3+3)^2})

Step-by-step explanation:

So we want to find the derivative of the rational equation:

y=\frac{x^2-2x}{x^3+3}

First, recall the quotient rule:

(\frac{f}{g})'=\frac{f'g-fg'}{g^2}

Let f be x^2-2x and let g be x^3+3.

Calculate the derivatives of each:

f=x^2-2x\\f'=2x-2

g=x^3+3\\g=3x^2

So:

\frac{dy}{dx}=(\frac{x^2-2x}{x^3+3})'

Use the above format:

\frac{dy}{dx}=\frac{f'g-fg'}{g^2}\\\frac{dy}{dx}=(\frac{(2x-2)(x^3+3)-(x^2-2x)(3x^2)}{(x^3+3)^2})

And that's our answer :)

(If you want to, you can also expand. However, no terms will be canceled.)

8 0
3 years ago
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