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igomit [66]
3 years ago
11

PLEASE HURRY

Mathematics
1 answer:
s2008m [1.1K]3 years ago
8 0

Answer:

1.25p

Step-by-step explanation:

p = amount raised last year

amount raised this year = p +(25% of p)

=1 p+0.25p

=p(1+0.25)

=1.25p

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ITEMS
VLD [36.1K]

Answer:

mp=160

dis=40

now,

sp=mp-dis

=Rs. 160-Rs.40

=Rs. 120

7 0
3 years ago
find the value of w and then x. round side lengths to the nearest tenth and angle measures to the nearest degree​
marin [14]

Answer:

<em>w = 7.7 units; x = 44°</em>

Step-by-step explanation:

4 0
3 years ago
Find the slope of the line passing through the points (-3,4) and (2,1)
maksim [4K]
Answer is d. -5/3 because y2-y1 =x2-x1
8 0
3 years ago
Read 2 more answers
Find the midpoint between the two points. A(2,-1) and B(-6,0)!! Pleaseee
Illusion [34]

Answer:

hope it helps you .......

5 0
3 years ago
Gribbles are small, pale white, marine worms that bore through wood. While sometimes considered a pest since they can wreck wood
Stells [14]

<u>Answer with explanation:</u>

As per given , we have

A sample of 50 gribbles finds an average length of 3.1 mm with a standard deviation of 0.72.

i.e. n= 50

Degree of freedom = n-1=49

\overline{x}=3.1\ mm

s=0.72\ mm

The point estimate of the population mean is equals to the sample mean.

i.e. The best estimate for the length of gribbles= 3.1 mm

Also, population standard deviation is unknown , then the confidence interval would be :

E=t_{\alpha/2, df}\dfrac{s}{\sqrt{n}}

For df= 49 and significance level of 0.05 , the t- value (using t-distribution table) would be :

t_{0.05/2, 49}=t_{0.025, 49}= 2.010

Now, Margin of error : E=(2.010)\dfrac{0.72}{\sqrt{50}}

=0.204664986747\approx0.20

95% confidence interval : (\overline{x}-E,\ \overline{x}+E)

i.e.\ (3.1-0.20, 3.1+0.20)=(2.90,\ 3.30)

3 0
4 years ago
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