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iren [92.7K]
3 years ago
6

Use the equation 135⋅42=5,670 and what you know about fractions, decimals, and place value to explain how to place the decimal p

oint when you compute (1.35)⋅(4.2).
Mathematics
1 answer:
Jobisdone [24]3 years ago
7 0

7x + 4 = 9

7x + 4 = 19

2x = 19 - 4

7x = 15

x= 15 – 7

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Find the length of side w.
9966 [12]

Hey there! I'm happy to help!

To find this other side given an angle and a side, we will use a trigonometric function. The three basic ones are sine, cosine, and tangent. You can remember these and what what they are using the mnemonic "soh cah toa".

SOH: Sine= Opposite/Hypotenuse

CAH: Cosine= Adjacent/Hypotenuse

TOA: Tangent= Opposite/Adjacent

We see that the sides involved are the opposite and hypotenuse.

Therefore, we can write this equation.

sin40= w/28

We multiply both sides by 28 to isolate the w.

28×sin40=w

Now, we find the sine of 40 on our calculator and then we multiply it by 28.

w≈18

Therefore, the answer is 18 cm.

I hope that this helps! Have a wonderful day!

4 0
3 years ago
Please help me 100 points and brainliest <br> Which net represents this solid figure?
Contact [7]

The one you picked, on the bottom left is correct

The top two both have rectangles and triangles, making them most likely triangular prisms. To the bottom right, the net represents a cube, which is incorrect, because the figure is supposed to be a rectangular prism.

7 0
2 years ago
Read 2 more answers
A=1+Prt solve for p
lilavasa [31]

A=1+Prt\\\\Prt=A-1\\\\P=\dfrac{A-1}{rt}

4 0
3 years ago
Evaluate C_n.xP^xQn-x For the given n=7, x=2, p=1/2
r-ruslan [8.4K]

Answer:

The value of given expression is \frac{21}{128}.

Step-by-step explanation:

Given information: n=7, x=2, p=1/2

q=1-p=1-\frac{1}{2}=\frac{1}{2}

The given expression is

C(n,x)p^xq^{n-x}

It can be written as

^nC_xp^xq^{n-x}

Substitute n=7, x=2, p=1/2 and q=1/2 in the above formula.

^7C_2(\frac{1}{2})^2(\frac{1}{2})^{7-2}

\frac{7!}{2!(7-2)!}(\frac{1}{2})^2(\frac{1}{2})^{5}

\frac{7!}{2!5!}(\frac{1}{2})^{2+5}

\frac{7\times 6\times 5!}{2\times 5!}(\frac{1}{2})^{2+5}

21(\frac{1}{2})^{7}

\frac{21}{128}

Therefore the value of given expression is \frac{21}{128}.

7 0
3 years ago
training for a cycle race in the first week if I was 195 miles in the second we can manage is 243 Miles what is the percentage i
Ivahew [28]

Answer:

24.61%

Step-by-step explanation:

The distance covered in first week = 195 miles

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We need to find the percentage increase in distance​. It can be calculated as follows :

\%=\dfrac{243-195}{195}\times 100\\\\=24.61\%

So, the increase in distance is equal to 24.61%.

4 0
3 years ago
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