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3 years ago

Please help on this math homework !

Mathematics

2 answers:

Mrac [35]3 years ago

8 0

Our two points are (2,-3) and (8,-9). To find the distance between these two points, we can use the distance formula: d = $\sqrt{(x_{2}-x_{1})^2 + (y_{2} - y_{1})^2 }$ .

Plug in values and solve for d:

d = $\sqrt{(8-2)^2 + (-9 - -3)^2\\}$

d = $\sqrt{(6)^2 + (-6)^2}$

d = $\sqrt{36 + 36}$

d = $\sqrt{72}$

The correct answer is C - $\sqrt{72}$

Hope this helps!! :)

Savatey [412]3 years ago

6 0

Answer:It's c

I already did it lesson

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Two lines have a slope of 3 and different y-intercepts how many solutions will this system have

Taya2010 [7]

Answer:

0 solutions / no solutions

Step-by-step explanation:

If two lines have the same slope but different y-intercepts, it means that they are parallel.

For example, we have two lines:

y = x

y = x + 1

Both lines have the same slope of 1, but different y - intercepts. Because each equation increases the x and y at the same right (slope) but started at different points, the two equations will never touch.

It's similar to two runner who run at the same pace. If one runner started 50 meters ahead, that runner will always be ahead 50 meters (y-intercept) because they both run at the same rate.

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2 years ago

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3 years ago

In 1875 an estimated twelve-and-a-half trillion locusts appeared in Nebraska.Write the number of locusts in scientific notation.

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Step-by-step explanation:

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3 years ago

Suppose Upper F Superscript prime Baseline left-parenthesis x right-parenthesis equals 3 x Superscript 2 Baseline plus 7 and Upp

Sedaia [141]

It looks like you're given

F'(x) = 3x² + 7

and

F (0) = 5

and you're asked to find F(b) for the values of b in the list {0, 0.1, 0.2, 0.5, 2.0}.

The first is done for you, F (0) = 5.

For the remaining b, you can solve for F(x) exactly by using the fundamental theorem of calculus:

$F(x)=F(0)+\displaystyle\int_0^x F'(t)\,\mathrm dt$

$F(x)=5+\displaystyle\int_0^x(3t^2+7)\,\mathrm dt$

$F(x)=5+(t^3+7t)\bigg|_0^x$

$F(x)=5+x^3+7x$

Then F (0.1) = 5.701, F (0.2) = 6.408, F (0.5) = 8.625, and F (2.0) = 27.

On the other hand, if you're expected to approximate F at the given b, you can use the linear approximation to F(x) around x = 0, which is

F(x) ≈ L(x) = F (0) + F' (0) (x - 0) = 5 + 7x

Then F (0) = 5, F (0.1) ≈ 5.7, F (0.2) ≈ 6.4, F (0.5) ≈ 8.5, and F (2.0) ≈ 19. Notice how the error gets larger the further away b gets from 0.

A better numerical method would be Euler's method. Given F'(x), we iteratively use the linear approximation at successive points to get closer approximations to the actual values of F(x).

Let y(x) = F(x). Starting with x₀ = 0 and y₀ = F(x₀) = 5, we have

x₁ = x₀ + 0.1 = 0.1

y₁ = y₀ + F'(x₀) (x₁ - x₀) = 5 + 7 (0.1 - 0) → F (0.1) ≈ 5.7

x₂ = x₁ + 0.1 = 0.2

y₂ = y₁ + F'(x₁) (x₂ - x₁) = 5.7 + 7.03 (0.2 - 0.1) → F (0.2) ≈ 6.403

x₃ = x₂ + 0.3 = 0.5

y₃ = y₂ + F'(x₂) (x₃ - x₂) = 6.403 + 7.12 (0.5 - 0.2) → F (0.5) ≈ 8.539

x₄ = x₃ + 1.5 = 2.0

y₄ = y₃ + F'(x₃) (x₄ - x₃) = 8.539 + 7.75 (2.0 - 0.5) → F (2.0) ≈ 20.164

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