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3 years ago

9

at the drive in it cost 5 dollars per vehicle plus 2 dollars per person in the vehicle construct an equations from this informat

ion

1 answer:

Mekhanik [1.2K]3 years ago

8 0

Answer:

5v+2d

Step-by-step explanation:

Hope I helped

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Is it true or false that 16.371 rounded to the nearest whole number 16 feet per second

rusak2 [61]

Answer:

true

Step-by-step explanation:

To round off a number to its nearest whole number, look at the first number after the decimal point. If the number is equal or greater than 5, add 1 to the number before the decimal point. If it is less than 5, add zero.

Because the first number after the decimal point is 3, which is less than 5, add zero to 16 . 16 + 0 = 16

If the number were 16.571, rounding off to the nearest whole number would give 17

4 0

3 years ago

The cost of oranges varies directly as the number of oranges sold. If 8 oranges cost $10.40, how many oranges can be bought for

alexdok [17]

Answer:

26

Step-by-step explanation:

if you can get 8 oranges for 10.40 then divide 10.40 by 8. you can get each orange for 1.3. you need to know how many oranges you can get for 33.8 so divide that by 1.3 and you get 26

6 0

3 years ago

Read 2 more answers

An ice cube is melting, and the lengths of its sides are decreasing at a rate of 0.8 millimeters per minute At what rate is the

julia-pushkina [17]

Answer:

The rate of decrease is: $43.2mm^3/min$

Step-by-step explanation:

Given

$l = 18mm$

$\frac{dl}{dt} = -0.8mm/min$ ---- We used minus because the rate is decreasing

Required

Rate of decrease when: $l = 18mm$

The volume of the cube is:

$V = l^3$

Differentiate

$\frac{dV}{dl} = 3l^2$

Make dV the subject

$dV = 3l^2 \cdot dl$

Divide both sides by dt

$\frac{dV}{dt} = 3l^2 \cdot \frac{dl}{dt}$

Given that: $l = 18mm$ and $\frac{dl}{dt} = -0.8mm/min$

$\frac{dV}{dt} = 3 * (18mm)^2 * (-0.8mm/min)$

$\frac{dV}{dt} = 3 * 18 *-0.8mm^3/min$

$\frac{dV}{dt} = -43.2mm^3/min$

<em>Hence, the rate of decrease is: 43.2mm^3/min</em>

8 0

3 years ago

What are the potential solutions of In(x^2-25)=0?

Maslowich

Answer:

$x =\pm \sqrt{26}$

Step-by-step explanation:

<u>Given </u><u>:</u><u>-</u><u> </u>

ln ( x² - 25 ) = 0

And we need to find the potential solutions of it. The given equation is the logarithm of x² - 25 to the base e . e is Euler's Number here. So it can be written as ,

<u>Equation</u><u> </u><u>:</u><u>-</u><u> </u>

$\implies log_e {(x^2-25)}= 0$

<u>In </u><u>general</u><u> </u><u>:</u><u>-</u><u> </u>

If we have a logarithmic equation as ,

$\implies log_a b = c$

Then this can be written as ,

$\implies a^c = b$

In a similar way we can write the given equation as ,

$\implies e^0 = x^2 - 25$

Now also we know that $a^0 = 1$ Therefore , the equation becomes ,

$\implies 1 = x^2 - 25 \\\\\implies x^2 = 25 + 1 \\\\\implies x^2 = 26 \\\\\implies x =\sqrt{26} \\\\\implies x = \pm \sqrt{ 26}$

<u>Hence</u><u> the</u><u> </u><u>Solution</u><u> </u><u>of </u><u>the</u><u> given</u><u> equation</u><u> is</u><u> </u><u>±</u><u>√</u><u>2</u><u>6</u><u>.</u>

6 0

3 years ago

Solve 5(x/2+3)=35 what is the answer

evablogger [386]

Answer:

x=8

Step-by-step explanation:

5(x/2+3)=35

x/2+3=35/5

x/2+3=7

x/2=7-3

x/2=4

x=4*2

x=8

8 0

3 years ago

Read 2 more answers