W2.5=80 , 80/2.5= 32 t=32
Answer:

Step-by-step explanation:
We will use the standard formula for half-life:

Where A₀ is the initial amount, a is the half-life, d is the time for one half-life, and t is the number of days.
So, we will substitute 1/2 for a and 24.3 for d. This yields:

We have a 3 gram sample. Therefore, our initial amount A₀ is 3:

And we want to find the remaining sample after 10 days. So, t=10. Substitute:

Use a calculator. So:

Therefore, for a 3 gram sample of Phosphorous-32 with a half-life of 24.3 days, after 10 days, there will be approximately 2.255 grams remaining.
(15√6 / √5)
<span>(15√6/√5) *(</span>√5/√5)
(15*√6*√5)/(√5*√5)
15*√30 / 5
3√30
14.
1. 7 × 7 = 49
2. 7 × 3 × 3 = 63
3. 7 × 3 × 4 = 84
4. 7 + 3 + 4 = 14
Hope that helps! Feel free to ask for a more explanation, if needed.
The cash price of the article is 88 cedis.
In this question, the article has a price, but paid in cash, there are two discounts.
- Price of 115 cedis.
- Discount of 15%, thus, 1 - 0.15 = 0.85 is paid, that is, the price is multiplied by 0.85.
- Discount of 10%, thus 1 - 0.1 = 0.9 is paid, that is, the price is also multiplied by 0.9.
Thus, the cash price is:

The cash price of the article is 88 cedis.
A similar question is given at: brainly.com/question/14738783