The answer is metal denting. I recommend formatting your question better
Answer:
The group reagent is H2S in the presence of NH4Cl .
Explanation:
Mn is fourth group radical in qualitative analysis ;
the group reagent is H2S in the presence of NH4Cl .
then Mn precipitates as buff coloured sulphide , which is soluble in HCl .
MnS + 2HCl ---------> MnCl2 + H2S
on heating the solution with NaOH with bromine water, manganesedioxide gets precipitated.
MnCl2 + 2NaOH --------> Mn(OH)2 + 2NaCl
Mn(OH)2 + O -------> MnO2 + H2O
whereas NiS is insoluble in HCl. the nickel chloride gives a scarlet red precipitate with dimethy gly oxime.
I think it is A rocky material; icy material
Answer:
% (COOK)2H2O = 37.826 %
Explanation:
mix: (COOK)2H2O + Ca(OH)2 → CaC2O4 + H2O
∴ mass mix = 4.00 g
∴ mass (CaC2O4)H2O = 1.20 g
∴ Mw (COOK)2H2O = 184.24 g/mol
∴ Mw (CaC2O4)H2O = 146.12 g/mol
∴ r = mol (COOK)2H2O / mol (CaC2O4)H2O = 1
- % (COOK)2H2O = (mass (COOK)2H2O / mass Mix) × 100
⇒ mass (COOK)2H2O = (1.20 g (CaC2O4)H2O)×(mol (CaC2O4)H2O / 146.12 g (CaC2O4)H2O)×(mol (COOK)2H2O/mol (CaC2O4)H2O)×(184.24 g (COOK)2H2O/mol (COOK)2H2O)
⇒ mass (COOK)2H2O = 1.513 g
⇒ % (COOK)2H2O = ( 1.513 g / 4 g )×100
⇒ % (COOK)2H2O = 37.826 %
Answer:
I attached a photo of balanced equations but thats as much as I can help.
Explanation:
