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Sergio [31]
3 years ago
13

Consider the above reaction. If some CO2 were removed from the container, what would the reaction do in an attempt to replace th

e CO2?
Chemistry
1 answer:
faltersainse [42]3 years ago
4 0

Answer:

See explanation

Explanation:

The reaction to be considered is shown below;

H2CO3<------->CO2 + H2O

We know  that when a constraint such as a sudden change in concentration, pressure or temperature is imposed on  a reaction system in equilibrium, the system has to adjust itself by shifting in a particular direction in order to cancel the constraint.

Now, if we remove CO2, the equilibrium position must shift to the right by the decomposition of more H2CO3 to establish equilibrium again.

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What is the pH of a 0.75 M HNO3 solution
Sauron [17]
Hello!

The dissociation reaction of HNO₃ is the following:

HNO₃ → H⁺ + NO₃⁻

This is a strong acid, so the concentration of HNO₃ would be the same as the concentration of H⁺. The formula for pH is the following:

pH=-log([H_3O^{+}])=-log(0,75M)=0,12

So, the pH would be 0,12

Have a nice day!
4 0
2 years ago
Read 2 more answers
Consider the following reaction:
RUDIKE [14]

Answer:

H+  + Cl-         +    OH-     +     Ca2+     -> Na+   +  Cl-    +   H2O

Explanation:

5 0
3 years ago
What is the definition of DNA in meiosis
Eddi Din [679]

In meiosis, DNA replication is followed by two rounds of cell division to produce four daughter cells, each with half the number of chromosomes as the original parent cell. The two meiotic divisions are known as meiosis I and meiosis II.

Explanation:

5 0
3 years ago
If an atom of thorium-234 were to undergo beta emission twice, which atom would result?
AnnZ [28]

Answer:

The answer to your question is  U-234

Explanation:

Data

Thorium-234

beta emission twice

Definition

Beta emission is when a beta particle (electron) is emitted from an atomic nucleus.

First beta emission

                                            ²³⁴₉₀Th   ⇒    ²³⁴₉₁Pa + e⁻

Second beta emission

                                            ²³⁴₉₁ Pa   ⇒  ²³⁴₉₂U  + e⁻

The atom will be Uranium-324

6 0
3 years ago
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IF 14.07*10^26 molecules of magnesium chloride was produced in the following reaction, how many grams of magnesium reacted?
Wittaler [7]

Answer:

56160grams

Explanation:

First, we need to convert the number of molecules of magnesium chloride (MgCl2) into moles by dividing by Avagadro's number (6.02 × 10^23 molecules)

n = nA ÷ 6.02 × 10^23

n = 14.07 × 10^26 ÷ 6.02 × 10^23

n = 14.07/6.02 × 10^(26-23)

n = 2.34 × 10^3 moles of MgCl2

The balanced reaction given in the question is as follows:

Mg + 2HCl → MgCl2 + H2

If 1 mole of Mg produced 1 mole of MgCl2

Then, 2.34 × 10^3 moles of Mg will also produce 2.34 × 10^3 moles of MgCl2.

Using mole = mass ÷ molar mass (MM)

Molar mass of Mg = 24g/mol

mass = mole × MM

mass = 2.34 × 10^3 × 24

mass = 56.16 × 10^3

mass = 56160grams.

6 0
3 years ago
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