You can figure out if two fractions are bigger by just cross multiplying the numerator and denominator of each fraction.
Multiply the 5 and 7, and then the 3 and 12. Be sure to start with the numerator of the first fraction.
5 * 7 = 35, 3 * 12 = 36
So
is bigger.
Answer:
0.8413 = 84.13% probability of a bulb lasting for at most 605 hours.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean 
and standard deviation 
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
The standard deviation of the lifetime is 15 hours and the mean lifetime of a bulb is 590 hours.
This means that 
Find the probability of a bulb lasting for at most 605 hours.
This is the pvalue of Z when X = 605. So
has a pvalue of 0.8413
0.8413 = 84.13% probability of a bulb lasting for at most 605 hours.
Answer:
x=0 x = 3/4
Step-by-step explanation:
32x^2 – 24x = 0
Factor out 8x
8x(4x -3)
Using the zero product property
8x = 0 4x-3 =0
x=0 4x=3
x=0 x = 3/4
After figuring out a common difference in this pattern, we can get further terms in the pattern:
1, -2, 2, -4, 0, -3, -1
Answer:
$742
Step-by-step explanation:
To solve this, you need to figure out what 6% of 700 dollars is and then add that to 700. The easiest way to find the percentage of a number is to set it up in the equation:
6/100 = x/700 where 6 is the percentage of 700 (out of 100 because you can only get up to 100 percent in this case) and x is 6 percent of 700. when you cross multiply, you get 100x = 4200. Then you divide both sides by 100 to get x by itself. This will give you x = 42 Add this to 700 for 742 as the total amount that will be paid. Sorry if this first half was a little confusing
