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Mashutka [201]
3 years ago
12

BRAINLIESTTT ASAP! PLEASE HELP ME :)

Mathematics
1 answer:
sergiy2304 [10]3 years ago
4 0

Answer:

\displaystyle Maximum: 11

Step-by-step explanation:

Convert this Quadratic Equation to Vertex Form by completing the square, \displaystyle y = a[x - h]^2 + k:

\displaystyle -5x^2 -10x + 6 \\ \\ -5x^2 - 10x + 25 + k \\ -5[x^2 + 2x - 5] + k \\ -5[x^2 + 2x + 1] + k → -5[x^2 + 2x + 1] + 11 → f(x) = -5[x + 1]^2 + 11 \\ \\ Vertex: [-1, 11]; 11 = Maximum

So as you can see, each time we broke the equation down, we used the formula \displaystyle [\frac{b}{2}]^2 to complete the square.

** In the Vertex Formula, −h gives the OPPOSITE terms of what they really are, so do not forget it.

I am joyous to assist you anytime.

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3 years ago
At a recent marathon, spectators lined the street near the starting line to cheer for the runners. The crowd lined up 5 feet dee
masha68 [24]

Answer:

29568 people cheered for the runners at the start of the race

Step-by-step explanation:

From the question, the crowd lined up 5 feet deep on both sides of the street for the first mile.

This lined up crowd could be related to a rectangle that is 1 mile long and 5 feet wide.

First, Convert 1 mile to feet

1 mile = 5280 feet

Hence, the length of the rectangle is 5280 feet and the width is 5 feet.

Now, we will determine how many 5 feet by 5 feet square we can get from the 5280 feet by 5 feet rectangle. To do that, we will divide 5280 feet by 5 feet

5280 feet ÷ 5 feet = 1056

Hence, from the rectangle, we can get 1056 5 feet by 5 feet square.

From the question, you estimate that 14 people can comfortably fit in a square that measures 5 feet by 5 feet,

∴ 14 × 1056 people will comfortably fit in the crowed lined up 5 feet deep on one side of the street for the first mile.

14 × 1056 = 14784 people

This is the amount of people that will comfortably fit in the crowed lined up 5 feet deep on one side of the street for the first mile.

Since the crowd lined up on both sides of the street, then

2 × 14784 people will comfortably fit in the crowed lined up 5 feet deep on both sides of the street for the first mile

2 × 14784 = 29568 people

Hence, 29568 people cheered for the runners at the start of the race.

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3 years ago
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Answer:

SAS congruence postulate. sweetheart.

Step-by-step explanation:


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