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3 years ago

11

Is kicking a ball a balanced forceps. dont search up

1 answer:

Sergeu [11.5K]3 years ago

6 0

Answer:

No.

Explanation:

When the ball is kicked it has Gravity, Normal Force and applied force.

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A pilot is flying from DFW to NYC. The air traffic controller directs him to fly 69° Northeast at 243 m/s. What is the y compone

kolezko [41]

Answer:

$v_{y} = 227$ m/s

Explanation:

Assumptions: 0° is true North, and 90° is east (along the x-axis).

To solve this problem we must use the expression:

$v_{y} = v_{0}sin(\theta)$

Where $v_{y}$ is the velocity in the y-direction (East), $v_{0}$ is the total velocity in the direction which the aircraft is travelling, and $\theta$ is the direction the aircraft is travelling (angle from the y-axis).

Using the equation above, we obtain the y-component of velocity

$v_{y} = (243)sin(69) = 226.86...$ m/s which is rounded to 227 m/s (due to the number of significant figures in the question).

8 0

4 years ago

A rocket initially at rest acceleration at a rate of 99.0meter/second^2. Calculate the distance covered by the rocket if it atta

Helga [31]

Distance traveled by the rocket= 1002 m

Explanation:

initial velocity= Vi=0

final velocity= V=445 m/s

time=4.5 s

Acceleration=a=99 m/s²

using kinematic equation

h= Vi t + 1/2 at²

h= 0(4.5) + 1/2 (99) (4.5)²

h=1002 m

Thus the distance traveled by the rocket= 1002 m

6 0

4 years ago

Why does ice float on water?

WITCHER [35]

Explanation:

Ice floats on water because it's alil water compacted into 1 shape which is heavier, ice is also a solid at 1st so solid things also can float on water

6 0

3 years ago

5. A motorcycle stuntman accelerates from rest to a maximum velocity of 35.2 m/s at the top of the

STALIN [3.7K]

Answer:

I need help with my password and I don’t know how to change it will you please help me

Explanation:

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2 years ago

In an attempt to reduce the extraordinarily long travel times for voyaging to distant stars, some people have suggested travelin

alexandr402 [8]

Answer:

a) $v=0.999124c$

b) $E=7.566*10^{22}$

c) $E_a=760 times\ larger$

Explanation:

From the question we are told that

Distance to Betelgeuse $d_b=430ly$

Mass of Rocket $M_r=20000$

Total Time in years traveled $T_d=36years$

Total energy used by the United States in the year 2000 $E_{2000}=1.0*10^20$

Generally the equation of speed of rocket v mathematically given by

$v=\frac{2d}{\triangle t}$

$v=860ly/ \triangle t$

where

$\triangle t=\frac{\triangle t'}{(\sqrt{1-860/ \triangle t)^2}}$

$\triangle t=\frac{36}{(\sqrt{1-860/ \triangle t)^2}}$

$\triangle t=\sqrt{(860)^2+(36)^2}$

$\triangle t=860.7532$

Therefore

$v=\frac{860ly}{ 860.7532}$

$v=0.999124c$

b)

Generally the equation of the energy E required to attain prior speed mathematically given by

$E=\frac{1}{\sqrt{1-(v/c)^2} }-1(20000kg)(3*10^8m/s)^2$

$E=7.566*10^{22}$

c)Generally the equation of the energy $E_a$ required to accelerate the rocket mathematically given by

$E_a=\frac{E}{E_{2000}}$

$E_a=\frac{7.566*10^{22}}{1.0*10^{20}}$

$E_a=760 times\ larger$

8 0

3 years ago