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2 years ago

5

Ideal mechanical advantage is equal to the displacement of the effort force divided by the displacement of the load.

1 answer:

ELEN [110]2 years ago

3 0

This would be false. hope this helps. good luck :)

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What are the output waveforms of the following waves, after passing through a transformer?

Ber [7]

The output waveforms after passing through the transformer actually depend on the type of transformer used. It could either be a step-up transformer (steps voltage up), or a step-down transformer (steps voltage down). Both transformers have an output voltage in a form of a sine wave.

8 0

3 years ago

What is amu?? How is 1amu=1.606*10*-27?

navik [9.2K]

Answer:

amu is atomic mass unit

All of elements hydrogen is the lightest.

Hydrogen is taken as a basic unit so it happened 1amu

So 1 amu must be hydrogen mass

If I am wrong,Pls tell me the true answer....

3 0

2 years ago

If the charges attracting each other in the preceding problem have equal magnitudes,show that the magnitude of each charge is 2.

Schach [20]

Answer:

The magnitude of each charge is $2.82\times10^{-6}\ C$

Explanation:

Suppose the two point charges are separated by 6 cm. The attractive force between them is 20 N.

We need to calculate the magnitude of each charge

Using formula of force

$F=\dfrac{kq^2}{r^2}$

Where, q = charge

r = separation

Put the value into the formula

$20=\dfrac{9\times10^{9}\times q^2}{(6\times10^{-2})^2}$

$q^2=\dfrac{(6\times 10^{-2})^2\times20}{9\times10^{9}}$

$q=\sqrt{\dfrac{(6\times 10^{-2})^2\times20}{9\times10^{9}}}$

$q=2.82\times10^{-6}\ C$

Hence, The magnitude of each charge is $2.82\times10^{-6}\ C$

6 0

2 years ago

Newton has Three Laws of Motion. Seat belts are used to help keep the passengers remaining in their seats during an accident. If

Jobisdone [24]

That is the 1st Law
Your welcome and PLEASE RATE TO KEEP HELPING YOU

5 0

3 years ago

Cierto volumen de gas se encuentra a 60°c de temperatura y 5atm de presión, es calentado hasta 140°c, estado en el cual ocupa un

earnstyle [38]

Answer:

V1 = 2221.33 L

Explanation:

The system is about a ideal gas. Then you can use the equation for ideal gases for a volume V1, temperature T1 and pressure P1:

$P_1V_1=nRT_1$ (1)

And also for the situation in which the variables T, V and P has changed:

$P_2V_2=nRT_2$ (1)

R: constant of ideal gases = 0.082 L.atm/mol.K

For both cases (1) and (2) the number of moles are the same. Next, you solve for n in (1) and (2):

$n=\frac{P_1V_1}{RT_1}\\\\n=\frac{P_2V_2}{RT_2}$

Next, you equal these equations an solve for T2:

$\frac{P_1V_1}{RT_1}=\frac{P_2V_2}{RT_2}\\\\V_1=\frac{P_2V_2T_1}{P_1T_2}$

Finally you replace the values of P2, V2, T1 and T2:

$V_1=\frac{(7atm)(680L)(140\°C)}{(60\°C)(5atm)}=2221.33\ L$

Hence, the initial volume of the gas is 2221.33 L

5 0

3 years ago