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garik1379 [7]
3 years ago
5

Ideal mechanical advantage is equal to the displacement of the effort force divided by the displacement of the load.

Physics
1 answer:
ELEN [110]3 years ago
3 0
This would be false. hope this helps. good luck :)
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what velocity must a 1340kg car have in order to havw the same momentum as a 2680 kg truck traveling at a velocity of 15m/s to t
kykrilka [37]
Car with a mass of 1210 kg moving at a velocity of 51 m/s.
2. What velocity must a 1340 kg car have in order to have the same momentum as a 2680 kg truck traveling at a velocity of 15 m/s to the west? 3.0 X 10^1 m/s to the west.

Hope i helped
Have a good day :)

 
6 0
4 years ago
Anyone know the answer to number 4…..please help me ASAP!
Damm [24]

Answer:

All planets have an elliptical orbit

all planets have roughly the same SHAPE of orbit

6 0
3 years ago
Read 2 more answers
You drive a car 640 m to the east, then 340 m to the north what is the magnitude of your displacement
mixer [17]

Magnitude of displacement = \sqrt{640^2 + 340^2}

Adding the squares gives displacement = \sqrt{525,200}

Displacement =  \sqrt{525,200} ≈ 724.7m

6 0
3 years ago
Consider steady heat transfer between two large parallel plates at constant temperatures of T1 = 210 K and T2 = 150 K that are L
snow_lady [41]

Answer:

Q=81.56\ W/m^2

Explanation:

Given that

T_1= 210 K

T_2= 150 K

Emissivity of surfaces(∈) = 1

We know that heat transfer between two surfaces due to radiation ,when both surfaces are black bodies

Q=\sigma (T_1^4-T_2^4)\ W/m^2

So now by putting the values

Q=\sigma (T_1^4-T_2^4)\ W/m^2

Q=5.67\times 10^{-8}(210^4-150^4)\ W/m^2

Q=81.56\ W/m^2

So rate of heat transfer per unit area

Q=81.56\ W/m^2

8 0
3 years ago
True or false: Only people that hold opinions of the group should get to express their opinion.
PilotLPTM [1.2K]

Answer:

true

Explanation:

this is fair to other people

5 0
3 years ago
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