Answer:
A) Does not change
B) Decrease
C) Increasing
D) Increasing
Explanation:
When it pushes it's volume is reduced by 1/3 because it's Area is constant there for only volume is decreased. Then the number of molecules don't change
A) don,t change
B) Decreases
C) Density is increased because it mass doesn't change. there for
Mass = Density * Volume
When Volume is decreasing to keep mass constant Density will be increased.
D) Pressure is increased according to the boil's law. it says that for fixed mass and fixed temperature pressure is inversely proportional to the volume. then volume decrease pressure increase
It might be a or d not too sure though
Answer:
48.22 kg
Explanation:
Applying the law of conservation of momentum,
Total momentum before collision = Total momentum after collision
Note: Since both skaters were initially at rest, then their total momentum before collision is equal to zero.
And the velocity of the second skater will be in opposite direction to the first.
0 = mv+m'v'.................... Equation 1
Where m = mass of the first skater, m' = mass of the second skater, v = final velocity of the first skater, v' = final velocity of the second skater.
make v' the subject of the equation
m' = -mv/v'................. Equation 2
Given: m = 62 kg, v = 0.7 m/s, v' = -0.9 m/s (opposite direction to the first)
Substitute into equation 1
m' = -62(0.7)/-0.9
m' = 48.22 kg
Answer:
vf = 3.27[m/s]
Explanation:
In order to solve this problem we must analyze each body individually and find the respective equations. The free body diagram of each body (box and bucket) should be made, in the attached image we can see the free body diagrams and the respective equations.
With the first free body diagram, we determine that the tension T should be equal to the product of the mass of the box by the acceleration of this.
With the second free body diagram we determine another equation that relates the tension to the acceleration of the bucket and the mass of the bucket.
Then we equalize the two stress equations and we can clear the acceleration.
a = 3.58 [m/s^2]
As we know that the bucket descends 1.5 [m], this same distance is traveled by the box, as they are connected by the same rope.
![x = \frac{1}{2} *a*t^{2}\\1.5 = \frac{1}{2}*(3.58) *t^{2} \\t = 0.91 [s]](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%2Aa%2At%5E%7B2%7D%5C%5C1.5%20%3D%20%5Cfrac%7B1%7D%7B2%7D%2A%283.58%29%20%2At%5E%7B2%7D%20%5C%5Ct%20%3D%200.91%20%5Bs%5D)
And the speed can be calculated as follows:
![v_{f}=v_{o}+a*t\\v_{f}=0+(3.58*0.915)\\v_{f}= 3.27[m/s]](https://tex.z-dn.net/?f=v_%7Bf%7D%3Dv_%7Bo%7D%2Ba%2At%5C%5Cv_%7Bf%7D%3D0%2B%283.58%2A0.915%29%5C%5Cv_%7Bf%7D%3D%203.27%5Bm%2Fs%5D)
Answer:
<u>A kangaroo hops 60 m to the east in 5 s. What is the kangaroo's average velocity? ... The kangaroo stops at a lake for a drink of water and then starts hopping again to the south. Each second, the kangaroo's velocity increases 2.5 m/s.</u>
