3 years ago

Ideal mechanical advantage is equal to the displacement of the effort force divided by the displacement of the load.

Physics

1 answer:

ELEN [110]3 years ago

3 0

This would be false. hope this helps. good luck :)

You might be interested in

2001240Determine the specific kinetic energy of a mass whose velocity is 40 m/s, in kJ/kg.

guapka [62]

Answer:

The specific kinetic energy of a mass is 0.8 kJ/kg

Explanation:

Given that,

Velocity = 40 m/s

Specific kinetic energy is the kinetic energy per unit mass.

We need to calculate the specific kinetic energy

Using formula of specific kinetic energy

$K.E=\dfrac{\dfrac{1}{2}mv^2}{m}$

$K.E=\dfrac{v^2}{2}$

Put the value into the formula

$K.E=\dfrac{40^2}{2}$

$K.E=800\ J/kg$

We know that,

1 kJ = 1000 J

or, 1J=0.001 KJ

The specific energy is

$K.E=800\times0.001$

$K.E=0.8\ kJ/kg$

Hence, The specific kinetic energy of a mass is 0.8 kJ/kg

6 0

3 years ago

Heat is best defined as

allochka39001 [22]

C. A flow of matter from one point to another.

7 0

4 years ago

Read 2 more answers

The discovery of which particle proved that the atom is not indivisible?

Blababa [14]

Maybe cuz your fat fat biches

8 0

4 years ago

A projectile is fired horizontally from a gun that is 54.0 m above flat ground, emerging from the gun with a speed of 330 m/s. (

krok68 [10]

Explanation:

Given

height of building (h)=54 m

Projectile velocity=330 m/s

initial vertical velocity $(u_y)=0$

Initial horizontal velocity $(u_x)=330 m/s$

Time taken to cover vertical height of 54 m

$h=ut+\frac{gt^2}{2}$

$54=0+\frac{9.81\cdot t^2}{2}$

$t=\sqrt{\frac{54\times 2}{9.81}}$

t=3.31 s

Horizontal distance traveled in this time

$R_x=u_x\times t$

$R_x=330\times 3.31=1094.94 m$

Vertical component of velocity when it hits the ground

v=u+at

$v=0+9.81\times 3.31=32.47 m/s$

3 0

3 years ago

I is the symbol for _________.

Studentka2010 [4]

C.) <span>I is the symbol for "Current"

Hope this helps!</span>

3 0

3 years ago

Read 2 more answers