Let x be the number.
Then:
(x)+(x+1)+(x+2)>102
(x)+(x+1)+(x+2)<109
x+x+1+x+2
3x+3>102
3x>102-3
3x>99
x>22
3x+3<109
3x<109-3
3x<106
x<35.33
Therefore, the number can be bigger than 22 but less than 35.333 to meet the requirements.
Hope I helped :)
Answer:
Step-by-step explanation:
13 + 21 = 34
Step-by-step explanation:
There are 7 books that can go in the first spot.
After a book has been placed in the first spot, there are 6 books left that can go in the second spot.
After that, there are 5 books that can go in the third spot.
So on and so forth.
So the number of ways is:
7×6×5×4×3×2×1 = 7! = 5040
3x - 1 = 26
substitution property of equality
3x = 27
answer
3x = 27
Answer: The answer would be c = -5/3 in it's improper form, c = −1.6 in its decimal form (btw the tenth place is a recurring decimal), c = -1 2/3 in the mixed fraction form
Step-by-step explanation: Isolate the variable by dividing each side by factors that don't contain the variable.