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3 years ago

Last question I'm stuck on now.

Mathematics

1 answer:

Yanka [14]3 years ago

4 0

Answer:

This is kind of late, but I hope I could help maybe for a later assignment or assesment.

The estimates of y have become increasingly more precise, with some of the earlier ones having a margin of error of more than 0.8

None of the estimates support newton's theory that y=0

Most of the estimate support Einstein, or at least have a margin of error that accounts for einstien.

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How do I solve this? Step by step

shutvik [7]

Answer:

24.

Step-by-step explanation:

Substitute each instance of x with a 3.

That leaves us with 3^2 + 3x - 5 + 3^2 - 3x + 11.

Combine like terms.

2(3^2) + 6.

Simplify.

2(9) + 6

18 + 6

24.

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3 years ago

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271403 rounded to the nearest ten thousand

ella [17]

Answer:

271,403 is rounded to 270,000 because the 1403 before it is less than 5000, 4 and below drop it down, 5 or more bump it up.

Step-by-step explanation:

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3 years ago

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Amelia drives 10 miles in 20 minutes. If she drove three hours in total at the same rate, how far did she go? subquestion - how

olga nikolaevna [1]

Answer:

Amelia drove 90 miles in 3 hours.

Step-by-step explanation:

she drove 10 miles in 20 minutes

we multiply this by 3, and get

30 miles in an hour ( 60 minutes)

then we multiply this by 3 and get

90 miles in 4 hours (180 minutes) :)

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3 years ago

What is the volume of this cone?

olchik [2.2K]

Answer:

The volume of the cone is approximately 453.0 cm³

Step-by-step explanation:

The volume of a cone is one third that of a cylinder with the same height and radius. That gives us 1/3 πr²h, where r is radius and h is height.

However, we are not given the height of the cone, but the side length. We can work out the height using the Pythagorean theorem, as we have a right triangle with the height, base radius, and length. You may recall that the Pythagorean theorem states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of it's other two sides:

$a^2 = b^2 + c^2$

So we can find the height of the cone with that:

$10.8^2 = 7.4^2 + h^2\\h^2 = 10.8^2 - 7.4^2\\h^2 = 116.64 - 54.76\\h^2 = 61.88\\h = \sqrt{61.88}\\h \approx 7.9$

Now that we have the cone's height, we can solve for its volume:

$v = \frac{1}{3} \pi r^2 h\\v = \frac{1}{3} \pi \times 7.4^2 \times 7.9\\v = \frac{1}{3} \pi \times 54.76 \times 7.9\\v = \frac{1}{3} \pi \times 432.6\\v = \pi \times 144.2\\v \approx 453.0 cm^3$

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3 years ago

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Which example describes area

Aleks [24]

I believe C. Measuring the length from one end of the field tot he other would be the most reasonable answer, because Area = Length x Width

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3 years ago