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2 years ago

Which property do metalloids share with nonmetals

Chemistry

1 answer:

Vesnalui [34]2 years ago

5 0

Answer:

Explained below

Explanation:

Metalloids are elements that possess properties between that of metals and non - metals or that have properties that a re a combination of those of metals and non - metals. Whereas a metal is one that conducts electricity and heat very well.

Now, the property they both share is that they both possess valence orbitals which are highly de-localized over macroscopic volumes, thereby allowing both of them to be conductors of electricity although it has to be said that Metalloids don't conduct electricity as much as metals.

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Does the statement describe a scientific law?

ale4655 [162]

Answer:

I think it's C sorry if I am wrong

8 0

2 years ago

How many moles of koh are contained in 250 ml of a 2.0 m solution of koh

kotykmax [81]

.5 mols
Assuming that your 2.0 m is an M for molarity
I used the formula M=number of mold/L
Converted 250mL to .250L by dividing by 1000

4 0

3 years ago

A compound of a transition metal and iodine is 56.7% metal by mass.How many grams of the metal can be obtained from 630 g of thi

erma4kov [3.2K]

Answer:

357 g of the transition metal are present in 630 grams of the compound of the transition metal and iodine

Explanation:

In any sample of the compound, the percentage by mass of the transition metal is 56.7%. This means that for a 100 g sample of the compound, 56.7 g is the metal while the remaining mass, 43.3 g is iodine.

Given mass of sample compound = 630 g

Calculating the mass of iodine present involves multiplying the percentage by mass composition of the metal by the mass of the given sample;

56.7 % = 56.7/100 = 0.567

Mass of transition metal = 0.567 * 630 = 357.21 g

Therefore, the mass of the transition metal present in 630 g of the compound is approximately 357 g

4 0

3 years ago

a sample of compound determined to contain 1.71 g C and 0.287 g H. The corresponding empirical formula is

fiasKO [112]

Answer: The empirical formula is $CH_2$ .

Explanation:

Mass of C = 1.71 g

Mass of H = 0.287 g

Step 1 : convert given masses into moles.

Moles of C = $\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{1.71g}{12g/mole}=0.142moles$

Moles of H = $\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.287g}{1g/mole}=0.287moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = $\frac{0.142}{0.142}=1$

For H = $\frac{0.287}{0.142}=2$

The ratio of C: H = 1: 2

Hence the empirical formula is $CH_2$ .

4 0

3 years ago

8.7 Two products are formed in the following reaction in a 50:50 mixture. Would the resulting solution be optically active

k0ka [10]

Answer:

Yes. The solution would be optically active.

Explanation:

Diastereomer are defined as the image that is non mirror and non -identical. It is made up of two stereoisomers. They are formed when the two stereoisomers or more than two stereoisomers of the compound have the same configuration at the equivalent stereocenters.

In the given context, as the product given is a diastereomeric mixture, the product would have an optical activity in total.

So the answer is Yes.

4 0

2 years ago