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Ivan
3 years ago
11

Can Petroleum be mixed with water?

Chemistry
2 answers:
viktelen [127]3 years ago
7 0

Answer:

No

Explanation:

Liquid water is held together by hydrogen bonds. (Liquid water has fewer hydrogen bonds than ice.) Oils and fats not have any polar part and so for them to dissolve in water they would have to break some of water's hydrogen bonds. Water will not do this so the oil is forced to stay separate from the water.

Alik [6]3 years ago
5 0

Answer:

No

Explanation:

Petroleum cant be mixed with water coz petroleum is less dense than water so petroleum will float on water.

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3 years ago
A teacher puts two tablets in a glass of water. The teacher
ehidna [41]

This question is incomplete because the options are missing; here are the options:

Which of the following is LESS dense than water?

The spoon

The glass

The tablets

The bubbles

The correct answer to this question is The bubbles

Explanation:

In general, the density of materials and substances affects their buoyancy. This implies in water less dense materials will float and those with higher density will sink. In the situation presented, the only element that is less dense than water are bubbles; this is shown by the movement of the bubbles as these originate in the bottom of the glass of water but they rise to the surface, which shows they are less dense than water.

6 0
3 years ago
Read 2 more answers
Why hyberdization occurs?
Damm [24]
Because the resulting hybridized orbitals are more stable
8 0
3 years ago
Given the following formula for calculating the ionization energy of one-electron species such as Li2+, He+, and H, calculate th
Yuki888 [10]

Answer:

The answer is "32819.9 \ \frac{J}{mol}\\\\"

Explanation:

Boron: 5^{B}\to 1s^2 2s^2 2p^1

\Delta E=-2.18\times 10^{-18}\ \frac{J}{atom}\ (\frac{1}{\infity^2}-\frac{1}{n^2_{initial}})(z^2) (6.022\times 10^{23}\ \frac{atom}{mol})\\\\

      =-2.18\times 10^{-18}\ \frac{J}{atom}\ (0-\frac{1}{1})(5^2) (6.022\times 10^{23}\ \frac{atom}{mol})\\\\ =2.18\times 10^{-18}\times 25 \times 6.022\times 10^{23}\ (\frac{J}{mol})\\\\ =328.199 \times 10^{5}\ (\frac{J}{mol})\\\\ =32819 \times 10^{3}\ (\frac{J}{mol})\\\\ =32819.9 \ (\frac{J}{mol})\\\\

4 0
3 years ago
AT constant temperature, a gas is compressed from 5.5 L to 1 L. At 1 L, the pressure of the gas is 98.2 kPa. What was the origin
svet-max [94.6K]

We have that  the original pressure of this gas  is mathematically given as

P2=17.854 kPa

<h3>Boyle's law</h3>

Question Parameters:

AT constant temperature, a gas is compressed from 5.5 L to 1 L.

At 1 L, the pressure of the gas is 98.2 kPa

Generally the equation for Boyle's law   is mathematically given as

P1V1=P2V2

Therefore

P1=\frac{P2V2}{V1}\\\\P2=\frac{98.2*1}{5.5}

P2=17.854 kPa

For more information on Pressure visit

brainly.com/question/25688500

7 0
2 years ago
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