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Ivan
3 years ago
11

Can Petroleum be mixed with water?

Chemistry
2 answers:
viktelen [127]3 years ago
7 0

Answer:

No

Explanation:

Liquid water is held together by hydrogen bonds. (Liquid water has fewer hydrogen bonds than ice.) Oils and fats not have any polar part and so for them to dissolve in water they would have to break some of water's hydrogen bonds. Water will not do this so the oil is forced to stay separate from the water.

Alik [6]3 years ago
5 0

Answer:

No

Explanation:

Petroleum cant be mixed with water coz petroleum is less dense than water so petroleum will float on water.

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Which substance is a binary acid
elena-s [515]
<span>It is known that acids compounds contains hydrogen and produces hydrogen ion in water. A binary acid however is an acid that have two elements, one of the element has a hydrogen attached to it. Examples of binary acids are hydrogen fluoride (HF), hydrogen bromide (HBr) and hydrogen sulfide (H2S). In naming a binary acid, it has two rules; one, as pure compounds and two, as acid solutions. For pure compounds, start with the name ‘hydrogen’ and end the anion name with ‘-ide’. For acidic compounds, start with ‘hydro-‘, end the anion with ‘-ic’ and add ‘acid’.</span>
8 0
4 years ago
What ions and/or molecules (apart from water) are present in relatively large proportions in a solution of a weak acid hclo (aq)
matrenka [14]

HClO, perchloric acid is a weak acid. Unlike strong acids like HCl or H2SO4 it not dissociate completely but partially such that an equilibrium exists between the dissociated ions and the undissociated acid. The equilibrium is as shown below:

HClO + H2O ↔ H3O⁺ + ClO⁻

Since HClO is a weak acid, the reverse reaction is favored over the forward reaction. Thus apart from water, HClO will be present in large amounts.

3 0
3 years ago
95. Using the standard enthalpy of formation data in Appendix G, calculate the bond energy of the carbon-sulfur double bond in C
prohojiy [21]

Answer:

+523 kJ.

Explanation:

The following data will be used to calculate the average C-S bond energy in CS2(l).

S(s) ---> S(g)

ΔH = 223 kJ/mol

C(s) ---> C(g)

ΔH = 715 kJ/mol

Enthalpy of formation of CS2(l)

ΔH = 88 kJ/mol

CS2(l) ---> CS2(g)

ΔH = 27 kJ/mol

CS2(g) --> C(g) + 2S(g)

So we must construct it stepwise.

1: C(s) ---> C(g) ΔH = 715 kJ

2: 2S(s) ---> 2S(g) ΔH = 446 kJ

adding 1 + 2 = 3

ΔH = 715 + 446

= 1161 kJ

3: C(s) + 2S(s) --> C(g) + 2S(g) ΔH = 1161 kJ

4: C(s) + 2S(s) --> CS2(l) ΔH = 88 kJ

adding (reversed 3) from 4 = 5

ΔH = -1161 + 88

= -1073 kJ

5: C(g) + 2S(g) --> CS2(l) ΔH = -1073 kJ

6: CS2(l) ---> CS2(g) ΔH = 27 kJ

adding 5 + 6 = 7

ΔH = -1073 + 27

= -1046 kJ

7. C(g) + 2S(g) --> CS2(g) ΔH = -1046 kJ

Reverse and divide by 2 for C-S bond enthalpy

= -(-1046)/2

= +523 kJ.

8 0
3 years ago
How many grams are in 2.3 x10-4 moles of calcium phosphate ca3(po3)2
Airida [17]

Answer:

calcium phosphate has the formula Ca3(PO4)2, which has the mass of 310 grams/mol.

1 mol contains 310 grams

2.3*10^-4 moles contain  2.3*10^-4 * 310, which means 713*10^-4 grams, or 71.3 milligrams.

If you wrote the formula right and named the compound wrong, all you have to do is replace 310 with 278 and the answer will be 639.4*10^-4 grams, or 63.94 milligrams.

6 0
3 years ago
A block has a mass of 25 grams and a volume of 24.5 cm3 what is the<br> density of the block?
schepotkina [342]

Answer:

<h3>The answer is 1.02 g/cm³</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass of block = 25 g

volume = 24.5 cm³

The density of the block is

density =  \frac{25}{24.5}  \\  = 1.020408163...

We have the final answer as

<h3>1.02 g/cm³</h3>

Hope this helps you

7 0
3 years ago
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