1/(x^5) is equal to x^-5, by the definition of negative exponents.
80 plus 80 is equal to 160. It's like 8 plus 8 equals 16, just add a zero to the end to each numbers it's easier to think that way
Step-by-step explanation:
as the denominator (x+3) is in both you need only one denominator to be multiplied in first rational number .
<u>2</u><u>x</u><u> </u><u>(</u><u>x-2</u><u>)</u><u>. </u><u> </u><u> </u>+ <u>5</u><u>. </u><u> </u><u> </u><u> </u><u> </u><u> </u>
(x+3) (x-2). (x+3) (x-2)
<u>2</u><u>x</u><u>^</u><u>2</u><u>-</u><u>4</u><u>x</u><u> </u><u>+</u><u>5</u><u> </u>
<u>(</u>x+3) (x-2)
it's cannot be solved after that.
Answer:
a common factor would be 5m^4n^3 or 15m^2n^2
Step-by-step explanation:
not sure what terms they want you to choose from but anything that starts with a number (5,10,15,) and "m" would any number 5 would go into
Answer:
Both are equal
Step-by-step explanation:
Because 4.40 = 4.4