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3 years ago

Help it’s due in thirty minutes!!!!

Mathematics

2 answers:

JulijaS [17]3 years ago

7 0

Answer:

Step-by-step explanation:

-5-(-9)

Elza [17]3 years ago

6 0

Answer:

-4

Step-by-step explanation:

-5 + ______ = -9

-5 + -4 = -9

You might be interested in

Write an expression to represents the product of 6 and the sum of w and 5

muminat

6(w+5) represents the product of 6 and the sum of w and 5. the product means multiplication, and the sum means addition.

6(w+5) also equals 6w+6(5), or 6w+30, because of the distribution property.

6 0

3 years ago

He purchased $12.00 worth of lemons and $4.00 worth of glasses to make the lemonade.

Allushta [10]

Answer:

<em>The minimum number of glasses of lemonade is 70</em>

Step-by-step explanation:

<u>Equations</u>

With the data provided, we can build a model for the profit that Michael gets for selling lemonade.

First, we set up the cost function. He purchased $12 in lemons and $4 in glasses. It makes a fixed cost of $16. He also spends $0.02 per glass of lemonade fot the sugar. Being x the number of glasses of lemonade Michael sells, the total cost is modeled by

C(x)=16+0.02x

The revenue for selling x glasses of lemonade is

R(x)=0.25x

The profit is

P(x)=R(x)-C(x)=0.25x-(16+0.02x)

P(x)=0.23x-16

To make profits:

0.23x-16>0

Solving for x

x>16/0.23

x>69.6

Since x must be an integer

The minimum number of glasses of lemonade is 70

7 0

3 years ago

Q1 A ball is thrown upwards with some initial speed. It goes up to a height of 19.6m and then returns. Find (a) The initial spee

lubasha [3.4K]

Answer:

(a) 19.6 ms⁻¹

(b) 2 s

(d) 4 s

Step-by-step explanation:

<u>Constant Acceleration Equations (SUVAT)</u>

$\boxed{\begin{array}{c}\begin{aligned}v&=u+at\\\\s&=ut+\dfrac{1}{2}at^2\\\\ s&=\left(\dfrac{u+v}{2}\right)t\\\\v^2&=u^2+2as\\\\s&=vt-\dfrac{1}{2}at^2\end{aligned}\end{array}} \quad \boxed{\begin{minipage}{4.6 cm}$s$ = displacement in m\\\\$u$ = initial velocity in ms$^{-1}$\\\\$v$ = final velocity in ms$^{-1}$\\\\$a$ = acceleration in ms$^{-2}$\\\\$t$ = time in s (seconds)\end{minipage}}$

When using SUVAT, assume the object is modeled as a particle and that acceleration is constant.

Acceleration due to gravity = 9.8 ms⁻².

When the ball reaches its maximum height, its velocity will momentarily be zero.

<u>Given values</u> (taking up as positive):

$s=19.6 \quad v=0 \quad a=-9.8$

$\begin{aligned}\textsf{Using} \quad v^2&=u^2+2as\\\\\textsf{Substitute the given values:}\\0^2&=u^2+2(-9.8)(19.6)\\0&=u^2-384.16\\u^2&=384.16\\u&=\sqrt{384.16}\\\implies u&=19.6\; \sf ms^{-1}\end{aligned}$

Therefore, the initial speed is 19.6 ms⁻¹.

Using the same values as for part (a):

$\begin{aligned}\textsf{Using} \quad s&=vt-\dfrac{1}{2}at^2\\\\\textsf{Substitute the given values:}\\19.6&=0(t)-\dfrac{1}{2}(-9.8)t^2\\19.6&=4.9t^2\\t^2&=\dfrac{19.6}{4.9}\\t^2&=4\\t&=\sqrt{4}\\\implies t&=2\; \sf s\end{aligned}$

Therefore, the time taken to reach the highest point is 2 seconds.

As the ball reaches its maximum height at 2 seconds, one second before this time is 1 s.

<u>Given values</u> (taking up as positive):

$u=19.6 \quad a=-9.8 \quad t=1$

$\begin{aligned}\textsf{Using} \quad v&=u+at\\\\\textsf{Substitute the given values:}\\v&=19.6+(-9.8)(1)\\v&=19.6-9.8\\\implies v&=9.8\; \sf ms^{-1}\end{aligned}$

The velocity of the ball one second before it reaches its maximum height is the <u>same</u> as the velocity one second after.

<u>Proof</u>

When the ball reaches its maximum height, its velocity is zero.

Therefore, the values for the downwards journey (from when it reaches its maximum height):

$u=0 \quad a=9.8 \quad t=1$

(acceleration is now positive as we are taking ↓ as positive).

$\begin{aligned}\textsf{Using} \quad v&=u+at\\\\\textsf{Substitute the given values:}\\v&=0+9.8(1)\\\implies v&=9.8\; \sf ms^{-1}\end{aligned}$

Therefore, the velocity of the ball one second before <u>and</u> one second after it reaches the maximum height is 9.8 ms⁻¹.

From part (a) we know that the time taken to reach the highest point is 2 seconds. Therefore, the time taken by the ball to travel from the highest point to its original position will also be 2 seconds.

Therefore, the total time taken by the ball to return to its original position after it is thrown upwards is 4 seconds.

4 0

1 year ago

A cardboard box without a lid is to have a volume of 4,000 cm3. Find the dimensions that minimize the amount of cardboard used.

Sholpan [36]

492sjnenkdoekkwjdjdkww

8 0

3 years ago

Brandy drove three times as far as Trisha. Together, they drove 48 miles. Which equation below can be used to find the number of

Xelga [282]

Answer:

$\textsf {C. 3x + x = 48}$