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4vir4ik [10]
3 years ago
5

Algebra 2 help please.

Mathematics
1 answer:
Oksanka [162]3 years ago
4 0
\frac{\sqrt{4^{3}}\sqrt[3]{x}\sqrt{y}}{\sqrt{z}} * \frac{\sqrt[5]{y^{2}}\sqrt[3]{z}}{\sqrt{x^{4}}} * \frac{\sqrt[5]{x^{3}}\sqrt[4]{x^{6}}}{\sqrt[3]{y^{2}}}
\frac{\sqrt{64}\sqrt[3]{x}\sqrt{y}}{\sqrt{z}} * \frac{\sqrt[5]{y^{2}}\sqrt[3]{z}}{x^{2}} * \frac{x^{2}\sqrt[5]{x^{3}}\sqrt[4]{x^{2}}}{\sqrt[3]{y^{2}}}
\frac{8\sqrt[3]{x}\sqrt{y}}{\sqrt{z}} * \frac{\sqrt[5]{y^{2}}\sqrt[3]{z}}{x^{2}} * \frac{x^{2}\sqrt[5]{x^{3}}\sqrt[4]{x^{2}}}{\sqrt[3]{y^{2}}}
\frac{8\sqrt{y}\sqrt[3]{xz}\sqrt[4]{x^{2}}\sqrt[5]{x^{3}y^{2}}}{\sqrt{z}\sqrt[3]{y^{2}}}
\frac{8\sqrt{yz}\sqrt[3]{xy^{2}z}\sqrt[4]{x^{2}}\sqrt[5]{x^{3}y^{2}}}{y^{2}z}
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That statement is True
3 0
3 years ago
-8p^4+12p^3+4p^4-8p^2+3p^2
Umnica [9.8K]

Answer:

-8p^4+12p^3+4p^4-8p^2+3p^2

=-8p^4+4p^4+12p^3-8p^2+3p^2

=-4p^4+12p^3-5p^2

=p^2(-4p^2+12p-5)

note: If you have to solve for X

there are steps according to formula

3 0
2 years ago
Find the midpoint of the line segment with the endpoints (1, 0) and (2, -10).
Mariulka [41]

Answer:

\bigl(\frac{3}{2},-5\bigr)

or in decimal form

(1.5,-5)

Step-by-step explanation:

The midpoint of the line with endpoints (x_1,y_1) and (x_2,y_2) is \bigl(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\bigr). just take the average between the points

so given the points (1,0) and (2,-10)

x_1=1

y_1=0

x_2=2

y_2=-10

the midpoint is found as follows:

\bigl(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\bigr)

\bigl(\frac{1+2}{2},\frac{0-10}{2}\bigr)

\bigl(\frac{3}{2},\frac{-10}{2}\bigr)

\bigl(\frac{3}{2},-5\bigr)

or in decimal form

(1.5,-5)

7 0
3 years ago
Given the following definition, compute Q(5). Q(n) = 0 if n = 0 2 if n = 1 4 if n = 2 Q(n − 1) + Q(n − 2) + Q(n − 3) if n > 2
aalyn [17]
We have 
Q(0)=0\\
Q(1)=2\\
Q(2)=4
and Q(n)=Q(n-1)+Q(n-2)+Q(n-3)\mbox{ when } n\ \textgreater \ 2.
So 
Q(3)=Q(2)+Q(1)+Q(0)=4+2+0=6\\
Q(4)=Q(3)+Q(2)+Q(1)=6+4+2=12\\
Q(5)=Q(4)+Q(3)+Q(2)=12+6+4=22.

3 0
2 years ago
How to solve -22-(6)(-9)/3
Sedaia [141]

Answer:

-4

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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