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aleksley [76]
3 years ago
8

Help me answer this nonsensical question!!!!!

Mathematics
2 answers:
timurjin [86]3 years ago
8 0
The answer to this problem is D.

We know that each month, he gets 4 coins to add to his collection so that would represent 4m. And we know that he started with 20. The last thing that we know is that we will need a greater than symbol to represent more than 50. Therefore the equation is
20 + 4m > 50.

Have a wonderful day ❤️
topjm [15]3 years ago
5 0

Answer:

D

Step-by-step explanation:

(if he gathers 4 coins each month you will need the variable by it. he was given 20 coins so it is added on to how many coins he has. plus it would be greater than because the question asked when he will have MORE than 50 coins.)

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Step-by-step explanation:

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Hello please help me need aanswer​
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\bold{\huge{\purple{\underline{ Answers :- }}}}

<h3><u>Answer </u><u>1</u><u> </u><u>:</u><u>-</u></h3>

If I were one of the students in Barangay then I shall prepare the design of kite by using the known properties of kites in mathematics.

For example, Symmetrical about its main diagonals, Adjacent side equals, Having two pairs of congruent triangle etc.

<h3><u>Answer </u><u>2</u><u> </u><u>:</u><u>-</u><u> </u></h3>

Design of kite assign to me

<u>Step </u><u>1</u><u> </u><u>:</u><u>-</u>

  • I shall take one paper and cut it like that the adjacent sides of paper are equal

<u>Reason </u><u>:</u><u>-</u>

  • <u>Adjacent </u><u>sides </u><u>of </u><u>kite </u><u>are </u><u>equal </u>

<u>Step </u><u>2</u><u> </u><u>:</u><u>-</u>

  • I shall take two thin sticks and paste it on the paper but sticks should intersect each other at 90°

<u>Reason</u><u> </u><u>:</u><u>-</u>

  • <u>Kite</u><u> </u><u>has </u><u>2</u><u> </u><u>diagonals </u><u>which </u><u>intersect </u><u>each </u><u>other </u><u>at </u><u>9</u><u>0</u><u>°</u><u> </u><u>.</u>

<u>Step </u><u>3</u><u> </u><u>:</u><u>-</u>

  • <u>Make </u><u>a </u><u>hole </u><u>in </u><u>the </u><u>one </u><u>of </u><u>the </u><u>end </u><u>point </u><u>of </u><u>a </u><u>longest </u><u>sides</u><u>. </u>

<u>Observation </u><u>:</u><u>-</u>

  • <u>The </u><u>kite </u><u>should </u><u>be </u><u>looked </u><u>like </u><u>that </u><u>it </u><u>having </u><u>two </u><u>pairs </u><u>of </u><u>congruent </u><u>triangle</u><u> </u><u>with </u><u>common </u><u>base. </u>

<h3><u>Answer </u><u>3</u><u> </u><u>:</u><u>-</u></h3>

  • The adjacent sides of the kites are equal that is 4cm and 6cm
  • The diagonals of the kite bisect each other at 90°
  • As kite is symmetrical from main diagonals , so it has two opposite and equal Angles that is 127°
  • The opposite angles at the end points of kite are congruent that is Angle D and Angle C
  • AC is the bisector of AB and AB is the bisector of AC .

[ Note :- Kindly refer the above attachment ]

<h3><u>Answer </u><u>4</u><u> </u><u>:</u><u>-</u></h3>

All mathematical concepts used in making kite are as follows :-

  • <u>Adjacent </u><u>sides </u><u>are </u><u>equal </u>
  • <u>Diagonal </u><u>intersect </u><u>each </u><u>other </u><u>at </u><u>9</u><u>0</u><u>°</u>
  • <u>Having </u><u>two </u><u>pairs </u><u>of </u><u>congruent </u><u>triangle </u><u>with </u><u>common </u><u>base </u>
  • <u>Symmetrical </u><u>about</u><u> </u><u>its </u><u>main </u><u>diagonal</u>
  • <u>Opposite </u><u>angles </u><u>at </u><u>the </u><u>end </u><u>points </u><u>are </u><u>equal</u>

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Can someone help me with this geometry question????
Gnesinka [82]

3.865in^2

It's (the area of the square minus the area of the circle) divided by 2.

So, Area of the square is 6x6=36

Area of the circle is (pi)*(radius=3)^2=28.27

36-28.27=7.73

7.73/2=3.865in^2

7 0
3 years ago
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