Answer:
The concept which best describes the change of the population is the derivative of
.
Step-by-step explanation:
Observe that the function
describes the amount of rabbits at the time t (in years) but no the rate of change of the population at a given instant. So you have to use the derivative of
to obtain that rate of change at any instant. For example, if we derivate the function
we obtain:

And if we want to find the rate of change at
years we evaluate
rabbits/year
Answer:
4
Step-by-step explanation:
If Judge is x years old and Eden is 6 years older, then Eden is x + 6 years old.
The second part tells us that Eden will be twice as old as Judge in two years.
This means that in two years: (Eden's age) = 2 * (Judge's age).
Since we know that Eden's age can be represented as x + 6 and Judge's age can be represented as x, we can write this: x + 6 = 2 * x
Simplify the equation:
x + 6 = 2x
6 = x = Judge's age (in two years)
If Judge is 6 two years later, then he must be 4 now.
To check our work, we can just look at the problem. Judge is 4 years old and Eden is 6 years older than Judge (that means Eden is 10 right now). Two years later, Eden is 12 and Judge is 6, so Eden is twice as old as Judge. The answer is correct.
Answer:
ok
Step-by-step explanation:
Answer:
a)

Step-by-step explanation:
The y intercept of g(x) is the value of g when x = 0.
In this problem

The y-intercept is

a)

The y-intercept is:

This is the correct answer
b)

The y-intercept is

This is an asymptote
c)

The y-intercept is

d)

The y-intercept is
[tex]f(0) = |0-4| = |-4| = 4.
Answer:
x = 
y = 
Step-by-step explanation:
![2x-3y=5\\5x=4y=14\\\\\left[\begin{array}{cc}2&-3\\5&-4\\\end{array}\right] \left[\begin{array}{c}x\\y\\\end{array}\right] =\left[\begin{array}{c}5\\14\\\end{array}\right]](https://tex.z-dn.net/?f=2x-3y%3D5%5C%5C5x%3D4y%3D14%5C%5C%5C%5C%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%26-3%5C%5C5%26-4%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D5%5C%5C14%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Let A = ![\\\left[\begin{array}{cc}2&-3\\5&-4\\\end{array}\right]](https://tex.z-dn.net/?f=%5C%5C%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%26-3%5C%5C5%26-4%5C%5C%5Cend%7Barray%7D%5Cright%5D)
The inverse of A multiplied by A = the identity matrix ![\left[\begin{array}{cc}1&0\\0&1\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%260%5C%5C0%261%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Inverse of A =
![\left[\begin{array}{ccc}-4&3\\-5&2\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-4%263%5C%5C-5%262%5C%5C%5Cend%7Barray%7D%5Cright%5D)
detA = ad - bc = 
Inverse of A = ![\left[\begin{array}{cc}\frac{-4}{7} &\frac{3}{7} \\\frac{-5}{7} &\frac{2}{7}\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Cfrac%7B-4%7D%7B7%7D%20%26%5Cfrac%7B3%7D%7B7%7D%20%5C%5C%5Cfrac%7B-5%7D%7B7%7D%20%26%5Cfrac%7B2%7D%7B7%7D%5C%5C%5Cend%7Barray%7D%5Cright%5D)
![\left[\begin{array}{ccc}x\\y\\\end{array}\right] = \left[\begin{array}{cc}\frac{-4}{7} &\frac{3}{7} \\\frac{-5}{7} &\frac{2}{7}\\\end{array}\right] \left[\begin{array}{ccc}5\\14\\\end{array}\right] = \left[\begin{array}{ccc}\frac{22}{7} \\\frac{3}{7} \\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%5C%5Cy%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Cfrac%7B-4%7D%7B7%7D%20%26%5Cfrac%7B3%7D%7B7%7D%20%5C%5C%5Cfrac%7B-5%7D%7B7%7D%20%26%5Cfrac%7B2%7D%7B7%7D%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%5C%5C14%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cfrac%7B22%7D%7B7%7D%20%5C%5C%5Cfrac%7B3%7D%7B7%7D%20%5C%5C%5Cend%7Barray%7D%5Cright%5D)