Answer:
120°
Step-by-step explanation:
I drew a picture that will make it easier to understand what's going on. Please see the attached image
In a rhombus, the diagonals bisect the opposite angles, and opposite angles are congruent.
Let's say angle 1 is x. The interior angles of a quadrilateral add up to 360°, so
30+30+30+30+2x=360
2x=240
x=120
angle 1 is 120°.
<span>an equation for the line in point-slope form and general form is :
y = ax+b a : </span>slope ; the <span>Passing through (x' ; y')
</span>y' = ax'+b
y-y' =a(x-x') and : x' =-5 y' =6
calculate a :
let : y = ax+b .....(D)
....<span>y=7x-1...</span>.(D')
.(D) perpendicular to(D') : slope (D) × slope (D') = -1
slope (D') = 7
slop(D)×(7 = -1
slope (D) = -1/7
equation for the line : y-y' =a(x-x')
y-6 =(-1/7) (x+5)
Your choices A and C are the same
but the decimal of 1/11 is 0.090909
so your answer would be 2.09
Answer:
d = 36°
Step-by-step explanation:
If ∠1 ≅ ∠2, thia means both angles are the same.
Given m∠1 = 3d + 2 and m∠KHG = 70
Substitute m∠KHG = 70 = m<1 into the expression to get d
m<1 = 180-m∠KHG
m<1 = 180-70
m<1 = 110
110 = 3d+2
subtarct 2 from both sides
110-2 = 3d+2-2
108 = 3d
rearranging
3d = 108
Divided both sides by 3;
3d/3 = 108/3
d = 36°
