2a^2b^3(4a^2+3ab^2-ab)=?
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is what I presume you actually meant. </span>
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Pull out the common factors of (4a^2+3ab^2-ab) and you will get </span>
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a(4a+3b^2 -b) </span>
Substitute this back into the original equation and you get
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2a^2b^3[a(4a+3b^2-b)] = </span>
2a^3b^3(4a+3b^2-b) =
<span>2a^3b^3(4a-b+3b^2)
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The answer is 12 i have answered a question just like dis disrigard the 1 and the genres just add the total number of cds
Answer:
b||c; c||d; b||d
Step-by-step explanation:
Substituting 10 for x, in the angle beside b we have
7(10)-5 = 70-5 = 65
In the angle beside c we have
10(10)+15 = 100+15 = 115
In the angle beside d we have
12(10)-5 = 120-5 = 115
In the angle beside we have
8(10)-25 = 80-25 = 55
The angle beside c has a vertical angle on the other side of c. This angle would be same-side interior angles with the angle beside b; this is because they are inside the block of lines made by b and c and on the same side of a, the transversal. These two angles are supplementary; this is because 65+115 = 180. Since these angles are supplementary, this means that b||c.
The angle beside c and the angle beside d would be alternate interior angles; this is because they are inside the block of lines made by c and d and on opposite sides of the transversal. These two angles are congruent; this means that c||d.
Since b||c and c||d, by the transitive property, b||d.
