(f o g)(x)=f(g(x))
so
h(x)=f(g(x))
hmm, see the differences
x+7=g(x)+1
x+6=g(x)
g(x)=x+6
so
h(x)=f(g(x))
hmm, see the differences
x+7=g(x)+1
x+6=g(x)
g(x)=x+6
I need help please it's due today
1 answer:
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Answer:
- doman: x ≠ 1
- range: y ≠ 7
Step-by-step explanation:
The domain is the horizontal extent of the graph, the set of x-values for which the function is defined. The range is the vertical extent of the graph, the set of y-values defined by the function.
<h3>Simplified</h3>The given function is undefined where its denominator is zero, at x=1. Everywhere else, it can be simplified to ...
The simplified function (3x+4) is defined for all values of x except x=1. The simplest description is ...
x ≠ 1
In interval notation, this is ...
(-∞, 1) ∪ (1, ∞)
<h3>Range</h3>
The simplified function is capable of producing all values of y except the one corresponding to x=1: 3(1)+4 = 7. The simplest description is ...
y ≠ 7
In interval notation, this is ...
(-∞, 7) ∪ (7, ∞)
Use this systems of equations to solve:
x = first antifreeze
y = second antifreeze
Isolate y.
x + y = 15
Subtract x from both sides.
y = -x + 15
Substitute y into the other equation.
.2x + .12(-x + 15) = .18(15)
Simplify.
.2x - .12x + 1.8 = 2.7
Subtract 1.8 from both sides.
.08x = .9
Divide both sides by .08
x = 11.25
Substitute x in the equation that we isolated y in.
y = -11.25 + 15
y = 3.75
11.25 L of the first antifreeze and 3.75 L of the second.
x = first antifreeze
y = second antifreeze
Isolate y.
x + y = 15
Subtract x from both sides.
y = -x + 15
Substitute y into the other equation.
.2x + .12(-x + 15) = .18(15)
Simplify.
.2x - .12x + 1.8 = 2.7
Subtract 1.8 from both sides.
.08x = .9
Divide both sides by .08
x = 11.25
Substitute x in the equation that we isolated y in.
y = -11.25 + 15
y = 3.75
11.25 L of the first antifreeze and 3.75 L of the second.