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3 years ago

PLEASE PLEASE PLEASE HELP I WILL GIVE BRAINLIEST

Mathematics

2 answers:

Gekata [30.6K]3 years ago

8 0

3.)x-3+5
4.)x-3x or x-1-2

gtnhenbr [62]3 years ago

7 0

3. X-3+5
4. X-3x or x-1-2 if you don't use x replace it for 0

hope this helps

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Brianna asks classmates how many pencils and erasers they carry in their bags. The mean number of pencils is 11. The mean number

NNADVOKAT [17]

Answer:

Only about 1/3 of the pencils have erasers.

3 0

3 years ago

(From Textbook) A company makes dog food out of chicken and grain. Chicken has 10 grams of protein and 5 grams of fat per ounce,

Doss [256]

Answer:

The company use 0 ounces of chicken and 100 ounces of grain in each bag of dog food in order to minimize cost.

Step-by-step explanation:

Let x be the number of ounces of chicken

let y be the number of ounces of grains

We are given that Chicken has 10 grams of protein and 5 grams of fat per ounce.

Chicken has protein in 1 ounce = 10

Chicken has protein in x ounces = 10x

Chicken has fat in 1 ounce = 5

Chicken has fat in x ounces = 5x

We are also given that grain has 2 grams of protein and 2 grams of fat per ounce

Grain has protein in 1 ounce = 2

Grain has protein in y ounces = 2y

Grain has fat in 1 ounce = 2

Grain has fat in y ounces =2y

Now we are given that . A bag of dog food must contain at least 200 grams of protein and at least 150 grams of fat.

So, equation becomes:

$10x+2y\geq 200$ ---A

$5x+2y\geq 150$ ---B

Since x and y represent the ounces .

So, $x\geq 0$ ---C and $y\geq 0$ ----D

Plot A ,B ,C and D on the graph

Refer the attached graph so , the corner points are (0,100),(10,50) and (30,0)

We are also given that chicken costs 10 cents per ounce and grain costs 1 cent per ounce

So, Cost function becomes : $c=10x+y$

At(0,100)

$c=10x+y$

$c=10(0)+100$

$c=100$

At(10,50)

$c=10x+y$

$c=10(10)+50$

$c=150$

At(30,0)

$c=10x+y$

$c=10(30)+0$

$c=300$

Minimum cost is 100 cents at (0,100)

So, the company use 0 ounces of chicken and 100 ounces of grain in each bag of dog food in order to minimize cost.

3 0

3 years ago

The fraction of defective integrated circuits produced in a photolithography process is being studied. A random sample of 300 ci

Olenka [21]

Answer:

The correct answer is

(0.0128, 0.0532)

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence interval $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

Z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$

For this problem, we have that:

In a random sample of 300 circuits, 10 are defective. This means that $n = 300$ and $\pi = \frac{10}{300} = 0.033$

Calculate a 95% two-sided confidence interval on the fraction of defective circuits produced by this particular tool.

So $\alpha$ = 0.05, z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{300}} = 0.033 - 1.96\sqrt{\frac{0.033*0.967}{300}} = 0.0128$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{300}} = 0.033 + 1.96\sqrt{\frac{0.033*0.967}{300}} = 0.0532$

The correct answer is

(0.0128, 0.0532)

4 0

3 years ago

birth weights in norway are normally distributed with a mean of 3570 g and a standard deviation of 500g. if the hospital officia

Svetradugi [14.3K]

Answer:

2630 g

Step-by-step explanation:

From the given information:

Given that:

mean (μ) = 3750 g

Standard deviation (σ) = 500

Suppose the hospital officials demand special treatment with a percentage of lightest 3% (0.03) for newborn babies;

Then, the weight of birth that differentiates the babies that needed special treatment from those that do not can be computed as follows;

P(Z < z₁) = 0.03

Using the Excel Formula; =NORMSINV(0.03) = -1.88

z₁ = - 1.88

Using the test statistics z₁ formula:

$z_1 = \dfrac{X-\mu}{\sigma}$

$-1.88 = \dfrac{X-3570}{500}$

By cross multiply, we have:

-1.88 × 500 = X - 3570

-940 = X - 3570

-X = -3570 + 940

-X = -2630

X = 2630 g

Hence, 2630 g is the required weight of birth that differentiates the babies that needed special treatment from those that do not

6 0

3 years ago

What is f(–3) for the function f(a) = –2a2 – 5a + 4?

shepuryov [24]

F(-3) = -2(-3)2 - 5(-3) +4
- 6 x 2 -15 + 4
- 12 -15 +4
- 27 + 4
-23

I believe this is how to solve the equation. I could be wrong.

4 0

3 years ago

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