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maxonik [38]
3 years ago
11

How do you solve the problem 2247 divided by 7?

Mathematics
2 answers:
Monica [59]3 years ago
4 0

Answer:

321

Step-by-step explanation:

2247÷7=321

Vera_Pavlovna [14]3 years ago
3 0

Answer:

321

Step-by-step explanation:

Shown in picture attached.

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A cube with side length 4p is stacked on another cube with side length 2q^2. What is the total volume of the cubes in factored f
inysia [295]
Volume of the cube with side 4p = 4p x 4p x 4p = 64p³

Volume of the cube with side 2q² =  2q² x  2q² x  2q² = 8q⁶

Total Volume = 64p³ +  8q⁶

Total Volume = (4p)³ + (2q²)³

Total Volume = (4p + 2q²)( ( 4p)² - (4p)(2q²) + (2q²)²)

Total Volume = (4p + 2q²)( 16p² - 8pq² + 4q⁴)

 
Answer:  (4p + 2q²)( 16p² - 8pq² + 4q⁴)
7 0
3 years ago
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5 students made an A in their Math quiz, 10 students made an B, 6 students made an C,
navik [9.2K]

Answer:

I think is C.............

5 0
2 years ago
​Find all roots: x^3 + 7x^2 + 12x = 0 <br> Show all work and check your answer.
Aliun [14]

The three roots of x^3 + 7x^2 + 12x = 0 is 0,-3 and -4

<u>Solution:</u>

We have been given a cubic polynomial.

x^{3}+7 x^{2}+12 x=0

We need to find the three roots of the given polynomial.

Since it is a cubic polynomial, we can start by taking ‘x’ common from the equation.

This gives us:

x^{3}+7 x^{2}+12 x=0

x\left(x^{2}+7 x+12\right)=0   ----- eqn 1

So, from the above eq1 we can find the first root of the polynomial, which will be:

x = 0

Now, we need to find the remaining two roots which are taken from the remaining part of the equation which is:

x^{2}+7 x+12=0

we have to use the quadratic equation to solve this polynomial. The quadratic formula is:

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Now, a = 1, b = 7 and c = 12

By substituting the values of a,b and c in the quadratic equation we get;

\begin{array}{l}{x=\frac{-7 \pm \sqrt{7^{2}-4 \times 1 \times 12}}{2 \times 1}} \\\\{x=\frac{-7 \pm \sqrt{1}}{2}}\end{array}

<em><u>Therefore, the two roots are:</u></em>

\begin{array}{l}{x=\frac{-7+\sqrt{1}}{2}=\frac{-7+1}{2}=\frac{-6}{2}} \\\\ {x=-3}\end{array}

And,

\begin{array}{c}{x=\frac{-7-\sqrt{1}}{2}} \\\\ {x=-4}\end{array}

Hence, the three roots of the given cubic polynomial is 0, -3 and -4

4 0
3 years ago
HELP PLEASE 26 POINTS!! please provide an explanation tooo!!!!
Mars2501 [29]

Answer:

B

Step-by-step explanation:

In the case of this distance, trying to imagine 5 x 10^6 is obviously way too ridiculous

8 0
2 years ago
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Let f(x) and g(x) be polynomials as shown below. Which of the following is true about f(x) and g(x)? f(x) and g(x) are not close
Mrrafil [7]

Answer:

  f(x) and g(x) are closed under multiplication because when multiplied, the result will be a polynomial.

Step-by-step explanation:

The set of all polynomials is <em>closed</em> under addition, subtraction, and <em>multiplication</em>, because performing any of these operations on a pair of polynomials will give a polynomial result.

__

<em>Comment on the question</em>

The wording is a bit strange, because f(x) and g(x) are elements of a set (of polynomials), so cannot be said to be "closed." "Closed" is a property of a set with respect to some function, it is not a property of an element of the set.

6 0
2 years ago
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