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maxonik [38]
3 years ago
11

How do you solve the problem 2247 divided by 7?

Mathematics
2 answers:
Monica [59]3 years ago
4 0

Answer:

321

Step-by-step explanation:

2247÷7=321

Vera_Pavlovna [14]3 years ago
3 0

Answer:

321

Step-by-step explanation:

Shown in picture attached.

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Use the following data sets to answer the question.
krek1111 [17]

Answer:

A. median is 12 but b has larger mean

7 0
3 years ago
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Earth has a radius of 3959 miles. A pilot is flying at a steady altitude of 1.8 miles above the earth's surface.
svp [43]
This is optional, but I find it easier to solve problems like this if you draw out what it might look like. That's what I've done for the attached image (see below). 

I've defined these points
A = center of earth
B = point just below the plane
C = plane's location
D = horizon (furthest point the pilot can see out)

Based on those point labels, we are given
AB = 3959 miles
BC = 1.8 miles
AD = 3959 miles
CD = x miles

Triangle ADC is a right triangle. So we can use the pythagorean theorem to find x
a^2 + b^2 = c^2
(AD)^2 + (CD)^2 = (AC)^2
3959^2 + x^2 = (AB+BC)^2
3959^2 + x^2 = (3959+1.8)^2
3959^2 + x^2 = 3960.8^2
15,673,681 + x^2 = 15,687,936.64
x^2 = 15,687,936.64 - 15,673,681
x^2 = 14,255.6399999988
x = sqrt(14,255.6399999988)
x = 119.396984886549
x = 119.4 <<--- rounding to the nearest tenth (one decimal place)

Final Answer: 119.4
Units are in miles

3 0
3 years ago
Juliet has 38 candy bars which she splits equally among 3 of her cousins. How many candy bars does each of Juliet’s cousins get?
Elodia [21]
Each of Juliets cousins get 12 candy bars and that leaves Juliet with only 2 candy bars.
6 0
3 years ago
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WRITE Math write a word problem involving money that requires dividing a decimal by a whole number. Include an estimate and a so
Rasek [7]
.014 times 7= .098 good luck 
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4 years ago
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Zadania są na zdjęciach. Pls mam z tym czas do jutra!!!
ira [324]

p + 2 = 5 ==> p = 3

3p + 2 = p + 3 ==> 2p = 2 ==> p = 1

3k + 5 = 2k + 2 ==> k = -3 (niemożliwe; lewa strona wagi ma większą wagę)

2w + 10 = 4w + 7 ==> 2w = 3 ==> w = 3/2

d + 9 = 3d + 2 ==> 2d = 7 ==> d = 7/2

W drugim zadanie każda litera reprezentuje wagę jednego z obiektów. Na przykład 3k + 4 reprezentuje całkowitą wagę 3 kół i 4 ciężarów, każdy o wadze 1 kg.

Trzecie zadanie to tylko połączenie dwóch pozostałych.

8 0
4 years ago
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