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Inessa05 [86]
3 years ago
14

Barbara found that six of the 24 students in her class on a cell phone what is the ratio of students that only sell phone to stu

dents that do not? Explain your reasoning to a classmate.

Mathematics
1 answer:
4vir4ik [10]3 years ago
7 0

Answer:

6:24 or 1:4

Step-by-step explanation:

If you don't have to simplify, then the answer would be 6:24, but if you do, then the answer would be 1:4.

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Consider the enlargement of the parallelogram. A smaller parallelogram with side lengths of one-third foot and x feet. A larger
balandron [24]

Answer:

Enlargement rate is 24

Step-by-step explanation:

Divide 8 by one third to get the enlargement rate. I hope this helps:)

4 0
3 years ago
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the area of a square is A = s^2, where s is the length of one side of the square. what is the side length s for each square ? th
vlada-n [284]

Answer:

18

Step-by-step explanation:

324 = s^2 -->

sqrt324 = s -->

sqrt(2^2 * 9^2) = s -->

2*9 = s -->

18 = s

5 0
3 years ago
Suppose a triangle has two sides of length 33 amd 37, and that the angle between these two sides is 120°. What is the length of
jeka57 [31]

Answer:

c = 60.65 cm

Step-by-step explanation:

Given that,

The two sides of a triangle are 33 cm and 37 cm.

The angle between these two sides is 120°.

We need to find the length of the third side of the triangle. Let c is the third side. Using cosine rule,

c^2=a^2+b^2-2ab\cos C

a = 33 cm, b = 37 cm and C is 120°

So,

c^2=(33)^2+(37)^2-2\times 33\times 37\cos (120)\\\\c=60.65\ cm

So, the length of the third side of the triangle is 60.65 cm.

7 0
3 years ago
The function p(t) represents the value of a new car t years after it was manufactured.
Yakvenalex [24]

Answer:


The value of the car is 0.94 times the value of the car the previous year.



5 0
3 years ago
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Plot 4/7 on the number line
erik [133]

Answer:

0.57, which is a number between 0 and 1

Step-by-step explanation:

The fraction 4/7 is approximately equal to 0.57 as a decimal, so you would plot 4/7 where 0.57 should go

8 0
3 years ago
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