Answer:
y = -2x + 5
Step-by-step explanation:
y = mx + b,
where m = slope, and b = y-intercept
y = -2x + 5
Answer:
3x=-x-60
Step-by-step explanation:
The line integral is the path of the function along a line having a continuous value.
The integral solved gives the value 111.
The given question is
![\int\limits^c {z}^2 \, dx+ {x}^2 \, dy+ {y} ^2\, dz](https://tex.z-dn.net/?f=%5Cint%5Climits%5Ec%20%7Bz%7D%5E2%20%5C%2C%20dx%2B%20%7Bx%7D%5E2%20%5C%2C%20dy%2B%20%7By%7D%20%5E2%5C%2C%20dz)
where C is the line from (1, 0, 0) to (4, 1, 3)
Here
x→ 1⇒ 4
y→ 0⇒1
z→ 0⇒ 3
Let t be defined be the range 0≤ t ≤ 1
Then x= 4t+1 : dx= 4dt
y= t ": dy= dt
z= 3t : dz= 3dt
Putting the values
![\int\limits^1_0{9t^2} \, 4dt + \int\limits^1_0 {16t^2+1+8t} \, 3dt +\int\limits^1_0 {t^2} \,3dt](https://tex.z-dn.net/?f=%5Cint%5Climits%5E1_0%7B9t%5E2%7D%20%5C%2C%204dt%20%2B%20%5Cint%5Climits%5E1_0%20%7B16t%5E2%2B1%2B8t%7D%20%5C%2C%203dt%20%2B%5Cint%5Climits%5E1_0%20%7Bt%5E2%7D%20%5C%2C3dt)
= [36(1)²- 36(0)²]+ 3 [16(1)² +1+8(1)] - 3 [16(0)² +1+8(0)] + [3(1)²- 3(0)² ]
= 36 +75-3+3
= 111
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You plug in n = 1 and solve, n= 2 then 3 etc.
n=1, a1 = 36-5(1-1) = 36
n=2, a2 = 36-5(2-1) = 31
n=3, a3 = 36-5(3-1) = 26
Answer:
-9.7
Step-by-step explanation:
we can do the opposite of everything that was done to get the resulting difference
so......
-8.4+6.4=-2
-2x19.4=-38.8
-38.8/4=-9.7
and to double check.......
-9.7x4=-38.8
-38.8/19.4=-2
-2-6.4=-8.4