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RoseWind [281]
3 years ago
6

Can someone please help me with this question?

Mathematics
1 answer:
Genrish500 [490]3 years ago
4 0
It’s numberrrrr 333333333333333
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In a shipment of 71 vials, only 13 do not have hairline cracks. If you randomly select 2 vials from the shipment, what is the pr
yanalaym [24]

Answer:

0.0313

Step-by-step explanation:

Given that in the shipment of 71 vials, only 13 do not have hairline cracks

Probability of not having a hairline cracks = \frac{13}{71}

If you randomly select 2 vials from the shipment

(Probability of not having a hairline cracks)' = \frac{13-1}{71-1} = \frac{12}{70}

what is the probability that none of the 2 vials have hairline cracks.

i.e (\frac{13}{71}) * (\frac{12}{70})

= 0.183 × 0.171

= 0.0313

Hence, the probability that none of the 2 vials have hairline cracks = 0.0313

6 0
3 years ago
Sara earns a basic salary of 14250 every month with an additional 12% commission on her sales. If Sara sold items worth AED 2226
never [62]

Answer:

A

Step-by-step explanation:

Commission: 22264*0.12=2671.68

Total pay: 14250+2671.68=16921.68

6 0
2 years ago
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In 1924, the tempature in Fairfield, Montana, dropped from 63 degrees to 21 in 12 hour. What was the average hourly change in te
Drupady [299]
Find the change
the change is 63-21=42
42 degrees in 12 hours
we want to find xdegrees/1hour
42/12=3.5 degrees per hour
8 0
3 years ago
I need help ASAP people
nirvana33 [79]

Answer:

point D: (2, -4)

Step-by-step explanation:

5 0
3 years ago
The weight of an object on mars varies directly is proportional as the weight of the object on earth a 75 pound object on earth
dedylja [7]

Answer:

It weighs 40 pounds on mars

Step-by-step explanation:

Direct proportion is the relationship between two variables when their ratio is equal to a constant value

  • It can be expressed as y = k x, where y varies directly as x and k is constant of variation
  • It can be expressed as  \frac{y_{1}}{x_{1}}=\frac{y_{2}}{x_{2}}=k

∵ The weight of an object on mars varies directly as the weight

    of the object on earth

∴ w(m) = k × w(e)

∵ The weight of the object on earth is 75 pound

∴ w(e) = 75

∵ The weight of this object on mars is 25 pounds

∴ w(m) = 25

- Substitute them in the equation of variation

∵ 25 = k × 75

- Divide both sides by 75

∴ \frac{1}{3} = k

∴ w(m) = \frac{1}{3} × w(e)

∵ An object weighs 120 pounds on earth

∴ w(e) = 120

- Substitute it in the equation of variation

∴ w(m) = \frac{1}{3} × 120

∴ w(m) = 40

∴ It weighs 40 pounds on mars

5 0
2 years ago
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