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Vika [28.1K]
3 years ago
11

Can u guys help me pleaseee

Physics
2 answers:
Lapatulllka [165]3 years ago
4 0

Answer:

I´ll help you, but what is the question?

Explanation:

Grace [21]3 years ago
3 0
Yessssssssssssssssssss
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One mole of an ideal gas does 2100 J of work as it expands isothermally to a final pressure 1.00 x 10^5Pa and volume of 0.025m^3
elena-s [515]

Answer:

(A) 0.004 m^3

(B) 48.11 K

Explanation:

Work, W = 2100 J

Pressure, P = 1 x 10^5 Pa

V2 = 0.025 m^3

(A) let the initial volume of the gas is V1.

W = P (V2 - V1)

2100 = 1 x 10^5 (0.025 - V1)

0021 = 0.025 - V1

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Thus, the initial volume of the gas is 0.004 m^3.

(B) Let the temperature of the gas is T

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1 x 10^5 x 0.004 = 1 x 8.314 x T

T = 48.11 K

Thus, the initial temperature of the gas is 48.11 K.

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