Complete the statements about the law of conservation of momentum.

An alpha particle (a He nucleus, containing two protons and two neutrons and having a mass of 6.64×10−27 kg ) traveling horizont

victus00 [196]

Answer:

A) d = 1.38 10-3 m, B) the velocity modulus remains constant and the velocity direction changes since the force is perpendicular

c) a = 1.94 10¹² m / s

d) the force is perpendicular to these two, that is, it points out of the page (positive z-axis)

e) E) the modulus of velocity remains constant because the force is perpendicular to the movement,

Explanation:

A) Let's use Newton's second law for this problem where the force is the magnetic force given by

F = m a

The magnetic force is

F = q v x B = q v B sin θ

Where the angle between the speed and the magnetite field is ce 90º so the sin 90 = 1

This implies that the acceleration is centripetal, which is given by

a = v² / R

We substitute

q v B = m v² / r

r = m v / qB

Let's calculate

r = 6.64 10⁻²⁷ 36.6 10³ / (2 1.6 10⁻¹⁹ 1.10)

r = 6,904 10⁻⁴ m

Diameter is twice the radius

d = 2 r

d= 1.38 10-3 m

B) The effect of the magnetic field is that the particle describes a circular motion, where the velocity modulus remains constant and the velocity direction changes since the force is perpendicular

C) the centripetal acceleration is

F = m a

q v B = m a

a = q v B / m

Let's calculate

a = 2 1.6 10⁻¹⁹ 36.6 10³ 1.10 / 6.64 10⁻²⁷

a = 1.94 10¹² m / s

D) Acceleration has the same direction of force toward the center of the circular orbit,

If we assume that the horizontal direction of the alpha particle is on the x-axis, the field is on the positive y-axis, so the force is perpendicular to these two, that is, it points out of the page (positive z-axis)

E) the modulus of velocity remains constant because the force is perpendicular to the movement, but the direction of the velocity does change in the direction of the force

6 0

3 years ago

Ryan runs 50 m north and then 50 m east. What is his displacement?

san4es73 [151]

Answer:

Explanation:

Distance and direction of an object's change in position from a starting point. Displacement. 3. Jermaine runs exactly 2 laps around a 400 meter track. What is the displacement? 0 ... David walks 3 km north, and then turns east and walks 4 km. ... A person walks 50 meters directly north, stops, and then travels 32 meters

3 0

3 years ago

A 250 GeV beam of protons is fired over a distance of 1 km. If the initial size of the wave packet is 1 mm, find its final size

Margarita [4]

Answer:

The final size is approximately equal to the initial size due to a very small relative increase of $1.055\times 10^{- 7}$ in its size

Solution:

As per the question:

The energy of the proton beam, E = 250 GeV = $250\times 10^{9}\times 1.6\times 10^{- 19} = 4\times 10^{- 8} J$

Distance covered by photon, d = 1 km = 1000 m

Mass of proton, $m_{p} = 1.67\times 10^{- 27} kg$

The initial size of the wave packet, $\Delta t_{o} = 1 mm = 1\times 10^{- 3} m$

Now,

This is relativistic in nature

The rest mass energy associated with the proton is given by:

$E = m_{p}c^{2}$

$E = 1.67\times 10^{- 27}\times (3\times 10^{8})^{2} = 1.503\times 10^{- 10} J$

This energy of proton is $\simeq 250 GeV$

Thus the speed of the proton, v $\simeq c$

Now, the time taken to cover 1 km = 1000 m of the distance:

T = $\frac{1000}{v}$

T = $\frac{1000}{c} = \frac{1000}{3\times 10^{8}} = 3.34\times 10^{- 6} s$

Now, in accordance to the dispersion factor;

$\frac{\delta t_{o}}{\Delta t_{o}} = \frac{ht_{o}}{2\pi m_{p}\Delta t_{o}^{2}}$

$\frac{\delta t_{o}}{\Delta t_{o}} = \frac{6.626\times 10^{- 34}\times 3.34\times 10^{- 6}}{2\pi 1.67\times 10^{- 27}\times (10^{- 3})^{2} = 1.055\times 10^{- 7}$

Thus the increase in wave packet's width is relatively quite small.

Hence, we can say that:

$\Delta t_{o} = \Delta t$

where

$\Delta t$ = final width

3 0

3 years ago

How do you know if a molecule is polar or nonpolar

Digiron [165]

Answer:

polar molecules are molecules that have an unequal distribution of charges. nonpolar molecules, the type of covalent bond are equally shared between two atoms or elements producing no charged ends

6 0

3 years ago

A car goes from 0 to 100 km/hr in 10 seconds. What is its acceleration

makvit [3.9K]

Answer:

a= 2.7 m/s^2

Explanation:

acceleration: a

speed: V

Vf = final speed

Vi= initial speed (initial = beginning)

100 km/hour --> m/s