Answer:
Kite
Perpendicular
Reflexive
HL
Step-by-step explanation: Just did it on edg 2021.
I think the answer to your question is 15 hope this helps
Step-by-step explanation:
S = { 1, 2, 3, 4, 5, 6 7, 8 }
n ( S ) = 8
Let A be the event of getting 4,
A = { 4 }
n ( A ) = 1
P ( A )
= n ( A ) / n ( S )
= 1 / 8
Therefore, the probability of spinning a 4 is 1 / 8.
S = { A, B, A, C, A, B }
n ( S ) = 6
Let Y be the event of getting C,
Y = { C }
n ( Y ) = 1
P ( Y )
= n ( Y ) / n ( S )
= 1 / 6
Therefore, the probability of spinning a C is 1 / 6.
Week 1-2 so it would be week one
For a better understanding of the solution given here please find the attached file which has the relevant diagram.
To answer this question we will have to make use of <u>the Isosceles Triangle Theorem</u> which states that the perpendicular bisector of the base of an isosceles triangle is also the angle bisector of the vertex angle. Thus, as a corollary we know that is EF is the angle bisector of the vertex angle ∠E, then, EF is the perpendicular bisector of the of the base DK.
Please follow the diagram of a complete understanding of the logic and the solution.
As EF is the angle bisector as given in the question, thus we will have:
.
Also, from the Theorem we know that KF will be half of DK and thus, KF will be:
centimeters.
Likewise, from the same theorem we have: 