<em><u>Complete Question:</u></em>
A colony of flowers is pollinated by hummingbirds and sunbirds. Let H represents the number of hummingbirds and S represent the number of sunbirds that must pollinate the colony so it can survive until next year.
6H+ 4S> 74
This year, 8 hummingbirds pollinated the colony. What is the least number of sun birds that must pollinate the colony to ensure that it will survive until next year?
<em><u>Answer:</u></em>
The least number of sun birds is 7
<em><u>Solution:</u></em>
Given inequality is:
6H + 4S > 74
Where,
H is the number of hummingbirds
S is the number of sunbirds
This year, 8 hummingbirds pollinated the colony
Substitute H = 8 in given inequality
6(8) + 4S > 74
48 + 4S > 74
Subtract 48 from both sides
48 + 4S - 48 > 74 - 48
4S > 26
Divide both sides by 4
S > 6.5
Hence the least number of sun birds is 7
Answer:
16:10, 4:2.5, 24:15
Step-by-step explanation:
i multiplied each value by 2 and 3 and on the second one i divided by 2
brainliest pls
I think it is E .I am thankfull in helping you
The answer is 47 because 3 5 7 9 11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 41 43 45 47
2/2 part of the equation is ≤ B
maybe 30/100 ≤ B
