Answer:
175°
Step-by-step explanation:
Bearing angles are usually measured clockwise from North. Reverse bearing angles differ from forward bearing angles by 180°. These relations and the usual angle sum relation for a triangle can be used to solve this problem.
Angle PQR will be the difference in the bearings from Q to P and Q to R:
∠PQR = 124° -46° = 78°
Triangle PQR is isosceles, so the base angle at P will be ...
∠QPR = (180° -78°)/2 = 51°
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The bearing from P to R will be 51° less than the bearing from P to Q. The bearing from P to Q is 180° more than the bearing from Q to P.
PR bearing = PQ bearing - ∠QPR
= PQ bearing - 51°
= (46° +180°) -51° = 175°
The bearing of R from P is 175°.
The expression that would go with this is 1x - 4
The "standard form" of a 2nd order poly is y = ax^2 + bx + c. Therefore, your 2 + 3x + x^2 in "standard form" is y = x^2 + 3x + 2.
Answer:
try 3.14 x 3.14 / 235.5 and that should be your awnser.
Step-by-step explanation:
the equation for diameter is d=2r which is pi times pi divided my the number. if i remeber correctly. lmk if im wrong
