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kow [346]
3 years ago
5

Write the equation of a line that has a slope of 3 and passes through the point (5, 7).

Mathematics
1 answer:
erastovalidia [21]3 years ago
4 0

Answer:

y = 3x - 8    

Step-by-step explanation:

All the options are written in slope-intercept ( y = mx + b) form. So, what we can do with the given information is write the equation in point-slope form first, then convert it to slope-intercept form.  

1) First, use the point-slope formula y-y_1 = m (x-x_1) to find the point-slope equation of the line. Substitute m, x_1, and y_1 for real values.

Since m represents the slope, substitute 3 in its place. Since x_1 and y_1 represent the x and y values of one point the line intersects, substitute the x and y values of (5,7) into the appropriate places in the formula as well. This gives the following equation of the line in point-slope form:  

y-7 = 3(x-5)

2) Now, isolate y in the above equation to find its slope-intercept form.

y-7=3(x-5)\\y-7 = 3x-15\\y = 3x -8

Thus, the answer would be the third option as it matches the result we received.

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Carlos is looking at moving into a new apartment. He found one that costs $750 per month, but they require that the cost of rent
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Answer:  2250

Step-by-step explanation:

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riadik2000 [5.3K]

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96 ---> 104 is +8

104 ---> 88 is -16

88 ---> 120 is +32

120 ---> 56 is -64  

So first we go down by 4, then up by 8, then down 16, then up 32, then finally down 64.  

The pattern of numbers is: -4, +8, -16, +32, -64  

Notice it's the powers of 2:  

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2^4 = 16

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each term doubles. Also each term alternates in sign. One is positive, then the next is negative and so on.  

The last difference is -64, which doubles to -128. Change the sign to positive to get +128  

Add 128 to the last term of 56 to get

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