Question

suppose that a particle accelerator is used to move two beams of particles in opposite directions. in a particular region, electrons move to the right at 4910 m/s4910 m/s and protons move to the left at 3485 m/s.3485 m/s. the particles are evenly spaced with 0.0288 m0.0288 m between electrons and 0.0662 m0.0662 m between protons. assuming that there are no collisions and that the interactions between the particles are negligible, what is the magnitude of the average current in this region?

Answer 1

The magnitude of average current is 2.02 * 10⁻¹⁴ A.

What is current?

A stream of charged particles, such as electrons or ions, travelling through an electrical conductor or a vacuum is known as an electric current. The net rate of electric charge flowing through a surface or into a control volume is how it is calculated.

Number of electrons passing per second = 4910/ 0.0662 = 74169.18

Number of proton passing per second = 3485/0.0662 = 52643.50

current due to electrons,

I = ne

= 74169.18 * 1.6 * 10⁻¹⁹

= 1.18 * 10⁻¹⁴ A

current due to protons,

I = ne

= 52643.50 * 1.6 *  10⁻¹⁹

= 0.84 * 10⁻¹⁴ A

total current  I = Ie + Ip

I =( 1.18 + 0.84 ) * 10⁻¹⁴ A

I = 2.02 * 10⁻¹⁴ A

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