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max2010maxim [7]
1 year ago
11

suppose that a particle accelerator is used to move two beams of particles in opposite directions. in a particular region, elect

rons move to the right at 4910 m/s4910 m/s and protons move to the left at 3485 m/s.3485 m/s. the particles are evenly spaced with 0.0288 m0.0288 m between electrons and 0.0662 m0.0662 m between protons. assuming that there are no collisions and that the interactions between the particles are negligible, what is the magnitude of the average current in this region?
Physics
1 answer:
dusya [7]1 year ago
4 0

The magnitude of average current is 2.02 * 10⁻¹⁴ A.

<h3 /><h3>What is current?</h3>

A stream of charged particles, such as electrons or ions, travelling through an electrical conductor or a vacuum is known as an electric current. The net rate of electric charge flowing through a surface or into a control volume is how it is calculated.

Number of electrons passing per second = 4910/ 0.0662 = 74169.18

Number of proton passing per second = 3485/0.0662 = 52643.50

current due to electrons,

I = ne

= 74169.18 * 1.6 * 10⁻¹⁹

= 1.18 * 10⁻¹⁴ A

current due to protons,

I = ne

= 52643.50 * 1.6 *  10⁻¹⁹

= 0.84 * 10⁻¹⁴ A

total current  I = Ie + Ip

I =( 1.18 + 0.84 ) * 10⁻¹⁴ A

I = 2.02 * 10⁻¹⁴ A

to learn more about current go to -

brainly.com/question/1256531

#SPJ4

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The frequency and wavelength of EM waves can vary over a wide range of values. Scientists refer to the full range of frequencies
mestny [16]

Complete question is;

The frequency and wavelength of EM waves can vary over a wide range of values. Scientists refer to the full range of frequencies that EM radiation can have as the electromagnetic spectrum. Electromagnetic waves are used extensively in modern wireless technology. Many devices are built to emit and/or receive EM waves at a very specific frequency, or within a narrow band of frequencies. Here are some examples followed by their frequencies of operation:

garage door openers: 40.0 MHz

standard cordless phones: 40.0 to 50.0 MHz

baby monitors: 49.0 MHz

FM radio stations: 88.0 to 108 MHz

cell phones: 800 to 900 MHz

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microwave ovens: 2450 MHz

wireless internet technology: 2.4 to 2.6 GHz

Which of the following statements correctly describe the various applications listed above? Check all that apply.

a.) All these technologies use radio waves, including low-frequency microwaves.

b.) All these technologies use radio waves, including high-frequency microwaves.

c.) All these technologies use a combination of infrared waves and high-frequency microwaves.

d.) Microwave ovens emit in the same frequency band as some wireless Internet devices.

e.) The radiation emitted by wireless Internet devices has the shortest wavelength of all the technologies listed above.

f.) All these technologies emit waves with a wavelength in the range of 0.10 to 10.0 m.

g.) All the technologies emit waves with a wavelength in the range of 0.01 to 10.0 km.

Answer:

B, D, E, F are the correct statements.

Explanation:

Looking at the options;

A) This is true because radio waves are electromagnetic radiation being used today in television, mobile phones, radios and other areas of communication technologies. And the examples given to us fall in the category of technologies that use radio waves.

B) microwaves usually have long wavelengths and low frequencies. However, sometimes they could have high frequencies usually more than radio waves. Thus, this option is correct.

C) This option is wrong because it's not all the listed technologies that use combination of infrared waves and high-frequency microwaves.

D) we are given the frequency of microwave ovens as 2450 MHz.

Converting to GHz gives; 2.45 GHz.

We are told that wireless internet technology has frequency between 2.4 to 2.6 GHz. Thus, microwave frequency falls in the same range as wireless internet technology and thus the statement is true.

E) we know that wavelength is inversely proportional to frequency. This means that the higher the frequency, the shorter the wavelength.

In the frequencies given to us, wireless internet technology have the highest frequency which means they have the shortest wavelength. The statement is true.

F) from the frequencies given to us, the smallest is garage door openers = 40.0 MHz = 40 × 10^(6) Hz while the biggest is 2.6 GHz = 2.6 × 10^(9) Hz

Formula for wavelength is;

Wavelength = speed of light/frequency

Speed of light = 3 × 10^(8) m/s

Thus;

Wavelength = (3 × 10^(8))/(40 × 10^(6))

Or wavelength = (3 × 10^(8))/(2.6 × 10^(9))

So,wavelength = 7.5 m or 0.12 m

This falls into the given range of 0.10 to 10.0 m.

Thus, the statement is true.

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given,                          

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