Answer:
93.75 m/s
Explanation:
Given:
The frequency of the sound = 750 Hz
The number of pistons making the sound = 8
Revolutions made by the engine = 2000 revolutions/ km
Thus,
the frequency of sound by 1 piston = 750 / 8 = 93.75 Hz
also, it is given that for every other revolution sound is made.
thus, for every 2 revolution sound is made
therefore,
Number of revolutions per second = 93.75 Hz × 2 = 187.5 rev/s
Now,
the speed of the car will be calculated as:
= Number of revolutions per second / Revolutions made by the engine
or
The speed of the car = 
or
The speed of the car = 0.09375 km/s = 93.75 m/s
Explanation:
the answer is 1835N that how best I can help
Using the equation:
Energy transferred = Charge x Potential difference
Rearrange for p.d:
V = E/Q
Substitute values:
V = 80/20
V = 4
<h3>
Answer:</h3>
117.6 Joules
<h3>
Explanation:</h3>
<u>We are given;</u>
- Force of the dog is 24 N
- Distance upward is 4.9 m
We are required to calculate the work done
- Work done is the product of force and distance
- That is; Work done = Force × distance
- It is measured in Joules.
In this case;
Force applied is equivalent to the weight of the dog.
Work done = 24 N × 4.9 m
= 117.6 Joules
Hence, the work done in lifting the dog is 117.6 Joules
Both momentum and kinetic energy are conserved in elastic collisions (assuming that this collision is perfectly elastic, meaning no net loss in kinetic energy)
To find the final velocity of the second ball you have to use the conversation of momentum:
*i is initial and f is final*
Δpi = Δpf
So the mass and velocity of each of the balls before and after the collision must be equal so
Let one ball be ball 1 and the other be ball 2
m₁ = 0.17kg
v₁i = 0.75 m/s
m₂ = 0.17kg
v₂i = 0.65 m/s
v₂f = 0.5
m₁v₁i + m₂v₂i = m₁v₁f + m₂v₂f
Since the mass of the balls are the same we can factor it out and get rid of the numbers below it so....
m(v₁i + v₂i) = m(v₁f + v₂f)
The masses now cancel because we factored them out on both sides so if we divide mass over to another side the value will cancel out so....
v₁i + v₂i = v₁f + v₂f
Now we want the final velocity of the second ball so we need v₂f
so...
(v₁i + v₂i) - v₁f = v₂f
Plug in the numbers now:
(0.75 + 0.65) - 0.5 = v₂f
v₂f = 0.9 m/s
