Answer:
The correct answer is -
Parent 1: RW, Parent 2: RR
Explanation:
In the given punnet square there are four offspring and it is a monohybrid cross between parent 1 and parent 2. The four offspring produced in this cross have RR, RR, RW, and RW alleles. By the genotype of the offsprings, it is clear that there are 50 percent pure or true-bred and 50 percent are heterozygous.
Each parent contribute two alleles and these alleles are independently assort in the zygote to form offspring so there must be R, R, R and W allele present in the parent
Parent 2 → R R
Parent 1 ↓ R RR RR (one allele (R) come from each parent in zygote)
W RW RW (one allele (R and W) come from each parent)
