Child abuse would be the best answer as child abuse is a common form of abuse
Answer:
61.39%
Explanation:
The percent yield of a substance can be calculated using the formula:
Percent yield = actual yield/theoretical yield × 100%
Based on the information provided on the reaction in this question, the theoretical yield is given as 99.2g while the actual yield is given as 60.9g.
Hence, the percent yield is calculated thus:
% yield = 60.9/99.2 × 100
% yield = 0.6139 × 100
% yield = 61.39%
The percent yield is 61.39%
Answer:
6.72M of HNO3
Explanation:
In the problem you are diluting the original HNO3 solution by the addition of some water. The final volume is:
290.7mL + 350.0mL = 640.7mL
And you are diluting the solution:
640.7mL / 350.0mL = 1.8306 times
As the original concentration was 12.3M, the final concentration will be:
12.3M / 1.8306 =
<h3>6.72M of HNO3</h3>
The given question is an incomplete question, the complete question is given below.
Use this equation to answer the questions that follow.
5 moles of oxygen gas are present. How many moles of 
will be produced with this amount of oxygen gas?
Answer : The moles of produced will be 3.33 moles.
Explanation : Given,
Moles of oxygen gas = 5 moles
Now we have to calculate the moles of .
The given balanced chemical equation is:
From the balanced chemical equation we conclude that,
As, 3 moles of 
gas react to produces 2 moles of gas
So, 5 moles of gas react to produces 
moles of gas
Therefore, the moles of produced will be 3.33 moles.
Answer: 1) 2Na + MgF2 —> 2NaF + Mg. Explain: You first look at how many F are in each side, then balance it, and look at the rest of the elements and balance them. Answer: 2) Mg + 2HCl —> MgCl2 + H2. Explain: look at the number of Cl in each side, balance it, and check to make sure both sides have the same amounts of each element. Answer: 3) Cl2 + 2KI —> 2KCl + I2. Explain: first look at the number of Cl on each side, and balance it, then look at the number of K on each side, and balance it, then check to make sure both sides are equal.
