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2 years ago

2. How many moles of NO3, will be produced with this amount of oxygen gas?

Chemistry

1 answer:

Thepotemich [5.8K]2 years ago

3 0

The given question is an incomplete question, the complete question is given below.

Use this equation to answer the questions that follow.

$3O_2(g)+N_2(g)\rightarrow 2NO_3(g)$

5 moles of oxygen gas are present. How many moles of $NO_3$ will be produced with this amount of oxygen gas?

Answer : The moles of $NO_3$ produced will be 3.33 moles.

Explanation : Given,

Moles of oxygen gas = 5 moles

Now we have to calculate the moles of $NO_3$ .

The given balanced chemical equation is:

$3O_2(g)+N_2(g)\rightarrow 2NO_3(g)$

From the balanced chemical equation we conclude that,

As, 3 moles of $O_2$ gas react to produces 2 moles of $NO_3$ gas

So, 5 moles of $O_2$ gas react to produces $\frac{2}{3}\times 5=3.33$ moles of $NO_3$ gas

Therefore, the moles of $NO_3$ produced will be 3.33 moles.

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2 years ago

How do the differences in the polyatomic ions po3 3- and po4 3- help you determine whether each ends in -ite or -ate?

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3 years ago

Convert 947400 s to cs

Gennadij [26K]

Answer:image

Explanation: image

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3 years ago

Consider the reaction between reactants s and o2: 2s(s)+3o2(g)→2so3(g)if a reaction vessel initially contains 7 mols and 9 mol o

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Answer: -

1 mol

Explanation: -

Number of moles of Sulphur S = 7

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The balanced chemical equation for the reaction is

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From the above reaction we can see that

3 mol of O2 react with 2 mol of S

9 mol of O2 will react with $\frac{2 mol S x 9 mol O2}{3 mol O2}$

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3 years ago

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1 year ago