Question

2. How many moles of NO3, will be produced with this amount of oxygen gas?

Answer 1

The given question is an incomplete question, the complete question is given below.

Use this equation to answer the questions that follow.

$3O_2(g)+N_2(g)\rightarrow 2NO_3(g)$

5 moles of oxygen gas are present. How many moles of $NO_3$ will be produced with this amount of oxygen gas?

Answer : The moles of $NO_3$ produced will be 3.33 moles.

Explanation : Given,

Moles of oxygen gas = 5 moles

Now we have to calculate the moles of $NO_3$.

The given balanced chemical equation is:

$3O_2(g)+N_2(g)\rightarrow 2NO_3(g)$

From the balanced chemical equation we conclude that,

As, 3 moles of $O_2$ gas react to produces 2 moles of $NO_3$ gas

So, 5 moles of $O_2$ gas react to produces $\frac{2}{3}\times 5=3.33$ moles of $NO_3$ gas

Therefore, the moles of $NO_3$ produced will be 3.33 moles.