2. How many moles of NO3, will be produced with this amount of oxygen gas?
1 answer:
The given question is an incomplete question, the complete question is given below.
Use this equation to answer the questions that follow.
5 moles of oxygen gas are present. How many moles of will be produced with this amount of oxygen gas?
Answer : The moles of produced will be 3.33 moles.
Explanation : Given,
Moles of oxygen gas = 5 moles
Now we have to calculate the moles of .
The given balanced chemical equation is:
From the balanced chemical equation we conclude that,
As, 3 moles of gas react to produces 2 moles of
gas
So, 5 moles of gas react to produces
moles of
gas
Therefore, the moles of produced will be 3.33 moles.
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Answer:
When the pressure increases to 90.0 atm , the volume of the sample is 0.01467L
Explanation:
To answer the question, we note that
P₁ = 1.00 atm
V₁ = 1.32 L
P₂ = 90 atm.
According to Boyle's law, at constant temperature, the volume of gas is inversely proportional to its pressure
That is P₁V₁ = P₂V₂
Solving the above equation for V₂ we have
that is V₂ =
=
or 0.01467L
Answer:
Take approx 41.7 mL of 12-M HCl in a 1.00-L flask and fill the rest of the volume with distilled water.
Explanation:
Hello,
In this case, for the dilution process from concentrated 12-M hydrochloric acid to 1.00 L of the diluted 0.50M hydrochloric acid, the volume of concentrated HCl you must take is computed by considering that the moles remain constant for all dilution processes as shown below:
Which can also be written in terms of concentrations and volumes:
Thus, solving for the initial volume or aliquot that must be taken from the 12-M HCl, we obtain:
It means that you must take approx 41.7 mL of 12-M HCl in a 1.00-L flask and fill the rest of the volume with distilled water for such preparation.
Best regards.