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3 years ago

Isomers have the same physical properties because the chemical formulas are identical. True False

1 answer:

5 0

The statement is False.
The molecular (chemical) formulas are same in case of isomers but the arrangement of atoms is different in them. The physical properties are determined by the arrangement of atoms within the molecule.

Since the arrangement of atoms is different in case of isomers, the Physical Properties will also be different.

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Which landform is created by moving water?

Virty [35]

Valleys i think !!! possibly

7 0

3 years ago

In a lead-acid battery, the electrodes are consumed. In this battery, Select one: a. the anode is PbO2. b. the cathode is Pb. c.

Gnoma [55]

Answer:

The correct answer is option e.

Explanation:

The lead acid battery consists lead as an anode and lead oxide as a cathode. Both the electrodes are suspended in dilute sulfuric acid which act as an electrolyte.

At anode: Oxidation

$Pb(s)+SO_4^{2-}(aq)\rightarrow PbSO_4(s)+2e^-$

At cathode: Reduction

$PbO_2+SO_4^{2-}(aq)+4H^+(aq)+2e^-\rightarrow PbSO_4(s)+2H_2O$

6 0

3 years ago

A student reacts 20.0 mL of 0.248 M H2SO4 with 15.0 mL of 0.195 M NaOH. Write a balanced chemical equation to show this reaction

Molodets [167]

Answer: The concentration of salt (sodium sulfate), sulfuric acid and NaOH in the solution is 0.0418 M, 0.0999 M and 0 M respectively.

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$ .....(1)

For NaOH:

Initial molarity of NaOH solution = 0.195 M

Volume of solution = 15.0 mL = 0.015 L (Conversion factor: 1 L = 1000 mL)

Putting values in equation 1, we get:

$0.195M=\frac{\text{Moles of NaOH}}{0.015L}\\\\\text{Moles of NaOH}=(0.195mol/L\times 0.015L)=2.925\times 10^{-3}mol$

For sulfuric acid:

Initial molarity of sulfuric acid solution = 0.248 M

Volume of solution = 20.0 mL = 0.020 L

Putting values in equation 1, we get:

$0.248M=\frac{\text{Moles of }H_2SO_4}{0.020L}\\\\\text{Moles of }H_2SO_4=(0.248mol/L\times 0.020L)=4.96\times 10^{-3}mol$

The chemical equation for the reaction of NaOH and sulfuric acid follows:

$2NaOH+H_2SO_4\rightarrow Na_2SO_4+2H_2O$

By Stoichiometry of the reaction:

2 moles of NaOH reacts with 1 mole of sulfuric acid

So, $2.925\times 10^{-3}$ moles of KOH will react with = $\frac{1}{2}\times 2.925\times 10^{-3}=1.462\times 10^{-3}mol$ of sulfuric acid

As, given amount of sulfuric acid is more than the required amount. So, it is considered as an excess reagent.

Thus, NaOH is considered as a limiting reagent because it limits the formation of product.

Excess moles of sulfuric acid = $(4.96-1.462)\times 10^{-3}=3.498\times 10^{-3}mol$

By Stoichiometry of the reaction:

2 moles of KOH produces 1 mole of sodium sulfate

So, $2.925\times 10^{-3}$ moles of KOH will produce = $\frac{1}{2}\times 2.925\times 10^{-3}=1.462\times 10^{-3}mol$ of sodium sulfate

For sodium sulfate:

Moles of sodium sulfate = $1.462\times 10^{-3}moles$

Volume of solution = [15.0 + 20.0] = 35.0 mL = 0.035 L

Putting values in equation 1, we get:

$\text{Molarity of sodium sulfate}=\frac{1.462\times 10^{-3}}{0.035}=0.0418M$

For sulfuric acid:

Moles of excess sulfuric acid = $3.498\times 10^{-3}mol$

Volume of solution = [15.0 + 20.0] = 35.0 mL = 0.035 L

Putting values in equation 1, we get:

$\text{Molarity of sulfuric acid}=\frac{3.498\times 10^{-3}}{0.035}=0.0999M$

For NaOH:

Moles of NaOH remained = 0 moles

Volume of solution = [15.0 + 20.0] = 35.0 mL = 0.035 L

Putting values in equation 1, we get:

$\text{Molarity of NaOH}=\frac{0}{0.050}=0M$

Hence, the concentration of salt (sodium sulfate), sulfuric acid and NaOH in the solution is 0.0418 M, 0.0999 M and 0 M respectively.

8 0

3 years ago

Choose the covalent compounds from the following choices Br2 MgS SO2 KF

Novosadov [1.4K]

Types of Bonds can be predicted by calculating the difference in electronegativity.

If, Electronegativity difference is,

Less than 0.4 then it is Non Polar Covalent Bond

Between 0.4 and 1.7 then it is Polar Covalent Bond

Greater than 1.7 then it is Ionic

For Br₂;

E.N of Bromine = 2.96

________

E.N Difference 0.00 (Non Polar Covalent Bond)

For MgS;

E.N of Sulfur = 2.58

E.N of Magnesium = 1.31

________

E.N Difference 1.27 (Ionic Bond)

For SO₂;

E.N of Oxygen = 3.44

E.N of Sulfur = 2.58

________

E.N Difference 0.86 (Polar Covalent Bond)

For KF;

E.N of Fluorine = 3.98

E.N of Potassium = 0.82

________

E.N Difference 3.16 (Ionic Bond)

Result: The Bonds in Br₂ and SO₂ are Covalent in Nature.

3 0

3 years ago

Which compound in each pair is more soluble in water?(b) Calcium phosphate or magnesium phosphate

Sidana [21]

larger is the value of $Ksp$ the higher will the solubility of solid in water.

What is called compound?

In chemistry, a compound is a substance made up of two or more different chemical elements combined in a fixed ratio.
When the elements come together, they react with each other and form chemical bonds that are difficult to break.
These bonds form as a result of sharing or exchanging electrons between atoms.

The equation for the dissociation of a solid MX in water is given below

MX(s) ⇄ Mⁿ⁺(aq) + Xⁿ⁻ (aq)

Assume s be the solubility of MX in pure water, then the equilibrium concentrations of ions are

[ Mⁿ⁺] = s

[ Xⁿ⁻ ] = s

The expression for the solubility product constant ( $Ksp$ ) is as follows

$Ksp$ = [ Mⁿ⁺] [ Xⁿ⁻ ]

= s²

That is, larger is the value of $Ksp$ the higher will the solubility of solid in water.

Learn more about compound

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6 0

2 years ago