Heat of vaporization is the heat required to vaporize unit mass of a substance at it's boiling point. The heat of vaporization or condensation of water is 2257 J/g.

It means that 1 g of water involves 2257 J energy during condensation or vaporization at its boiling point (100 C)

Given mass of water vapor that is condensing = 11.2 g

Calculating the heat released when 11.2 g of water vapor condenses in to liquid water at 100 $^{0}C$ :

$11.2 g *2257\frac{J}{g} = 25,278 J$

Rounding the final answer 25,278 J to three significant figures we get, 25,300 J

Therefore the correct answer is E. 25,300 J

6 0

4 years ago

A large balloon contains 233 L of neon at 22.0C and 760. Torr. If the balloon ascends to an altitude where the temperature is -

shepuryov [24]

Answer: The volume in the balloon at the higher altitude is 260 L

Explanation:

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 760 torr

$P_2$ = final pressure of gas = 511 torr

$V_1$ = initial volume of gas = 233 L

$V_2$ = final volume of gas = ?

$T_1$ = initial temperature of gas = $22.0^0C=(22.0+273)K=295K$

$T_2$ = final temperature of gas = $-52.0^0C=(-52.0+273)K=221K$

Now put all the given values in the above equation, we get:

$\frac{760\times 233}{295}=\frac{511\times V_2}{221}$

$V_2=260L$

The volume in the balloon at the higher altitude is 260 L

3 0

3 years ago