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3 years ago

MATCH THE FOLLOWING!!!

Chemistry

2 answers:

Svet_ta [14]3 years ago

6 0

Match each weather instrument with its description.

weather maps/satellite - used to help track air masses and fronts
Doppler radar - uses frequency waves to track particle movement
radiosonde - carried with a weather balloon
wind vane - points in the direction winds are coming from
psychrometer - uses two thermometers; a dry and wet bulb

prisoha [69]3 years ago

3 0

Answer: The correct matching sequence is:

1 -D , 2-C, 3-E, 4-B , 5-A

Explanation:

Weather maps/satellite:These are the satellites used to monitor the climate on the Earth in day and night.Like moc=vment of clouds, El Nino. La Nina ertc

Doppler radar is a system used to track the velocity or motion of the rain , storm or precipitation.It emit microwave signals to check the change in frequency of the wave due to the motion of the particles.

Radiosonde is an instrument carried away by balloon or any other means into different layers of atmosphere and sends information via radio.

Wind vane is an instrument used to show the direction of the wind. P

Psychrometer is an instrument used to measure atmospheric humidity.It consist of two thermometer that is wet bulb thermometer and dry bulb thermometer.

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3 years ago

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4 years ago

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Write the balanced chemical equation for the reaction of potassium metal (k) with water to yield potassium hydroxide.

Tanzania [10]

Reaction: 2K₍s₎ + 2H₂O₍l₎ → 2KOH₍aq₎ + H₂₍g₎.
K - potassium.
H₂O - water.
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H₂ - hydrogen.
s - solid phase.
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3 years ago

200.0 mL of 3.85 M HCl is added to 100.0 mL of 4.6 M barium hydroxide. The reaction goes to completion. What is the concentratio

Ede4ka [16]

Answer:

2.387 mol/L

Explanation:

The reaction that takes place is:

2HCl + Ba(OH)₂ → BaCl₂ + 2H₂O

First we calculate how many moles of each reagent were added:

HCl ⇒ 200.0 mL * 3.85 M = 203.85 mmol HCl

Ba(OH)₂ ⇒ 100.0 mL * 4.6 M = 460 mmol Ba(OH)₂

460 mmol of Ba(OH)₂ would react completely with (2*460) 920 mmol of HCl. There are not as many mmoles of HCl so Ba(OH)₂ will remain in excess.

Now we calculate how many moles of Ba(OH)₂ reacted, by converting the total number of HCl moles to Ba(OH)₂ moles:

203.85 mmol HCl * $\frac{1mmolBa(OH)_{2}}{2mmolHCl}$ = 101.925 mmol Ba(OH)₂

This means the remaining Ba(OH)₂ is:

460 mmol - 101.925 mmol = 358.075 mmoles Ba(OH)₂

There are two OH⁻ moles per Ba(OH)₂ mol:

OH⁻ moles = 2 * 358.075 = 716.15 mmol OH⁻

Finally we divide the number of OH⁻ moles by the total volume (100 mL + 200 mL):

716.15 mmol OH⁻ / 300.0 mL = 2.387 M

So the answer is 2.387 mol/L

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3 years ago